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Schach [20]
2 years ago
10

Simplify each expression by combining like terms. 1) 3y+4x-y+2x 2) 3y+2+3x-y+5x

Mathematics
1 answer:
SVEN [57.7K]2 years ago
8 0

Answer:

Step-by-step explanation:

1) 2y + 6x

2) 2y + 8x +2

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The Venn diagram shows all of the elements in sets A, B and ξ. Find the elements in (A ∩ B) U (A U B)’
marusya05 [52]

This is impossible to answer without knowing what the sets A and B contain (and what ξ even refers to - universal set?).

However, we have

(A U B)' = A' ∩ B'

so that

(A ∩ B) U (A U B)' = (A ∩ B) U (A' ∩ B') = (A U A') ∩ (B U B')

If ξ is indeed the universal set, then both A U A' = ξ and B U B' = ξ, so we end up with ξ ∩ ξ = ξ.

8 0
2 years ago
Solve for the variable. if necessary, round to the nearest tenth.
Yanka [14]

Answer:

b. 8 is the correct answet it's clearly

7 0
2 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
2 years ago
Find the intercepts of 2x-y=-4
-Dominant- [34]

Answer:

Y intercept: y=2x+4

And x intercept: x=1/2y-2

Step-by-step explanation:

7 0
2 years ago
4c-7.8 Evaluate the expression if c=4
slavikrds [6]
I hope this helps you



4.4-7,8


16-7,8


8,2
5 0
2 years ago
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