Question

Write the expression (−2)·(−2)·7·7·7·7·7 using exponents.

Answer 1

Answer:$(-2)^{2}*7^{5}$

Step-by-step explanation:

You have to group all of the same one's together and however many there is, you add that number as the exponent.

There were 2 "(-2)" so that became $(-2)^{2}$, and there were 5 "7" so that became $7^{5}$. You keep the symbol and put it together which became $(-2)^{2}*7^{5}$