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Troyanec [42]
2 years ago
14

Can someone help me with this Geometry question?

Mathematics
1 answer:
klasskru [66]2 years ago
4 0

Answer:

Ok ano po ba yan answer ko yan

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For what values of p is the value of the binomial 1.5p−1 smaller than the value of the binomial 1+1.1p by 4?
77julia77 [94]

Answer:

  p = -5  (only)

Step-by-step explanation:

It looks like we want to count solutions for ...

  (1.5p -1) = (1 +1.1p) -4

  0.4p = -2

  p = -2/0.4 = -5

For p having a value of -5, the binomial (1.5p -1) = -8.5 will be smaller than the value of (1 +1.1p) = -4.5 by 4.

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The value of 4 less than the product of 0.25 and x is greater than 6. What are all the possible values of x? SHOW YOUR WORK!
seraphim [82]

Answer:

0.25x - 4 > 6

Step-by-step explanation:

First, we would like to thank you for all of the additional support you offer at home. ... Subtract the absolute values. Multiply the denominators. 4. Reduce if necessary. 3. 10 x. 2. 3. 6. 30. = 1. 5. 3 ... 1 less than the product of 3 and m 3m – 1.

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3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0&lt;=t&lt;=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
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