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bixtya [17]
3 years ago
8

What is the solution of the following system of equations? 2x + y = -7 -3x - 2y = 10

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

the solution is    (-4, -3)

Step-by-step explanation:

Multiply the first equation by 2.  This produces 4x + 2y = -14.

Now combine this result with the second equation:

4x + 2y = -14

-3x - 2y = 10

------------------

 x          = -4

Subbing -4 for x in the first equation yields 2x - 4 = -7, or 2x = -3.  

Then x = -3/2, and the solution is    (-4, -3)

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ivann1987 [24]
Isolate the variable by dividing each side by factors that don't contain the variable.

a=- \frac{ x^{2}- \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2} ,- \frac{ x^{2}+ \sqrt{( x^{3} + x^{2} b+12x-72(x-2)-2x} }{x-2}

Solve for b by simplifying both sides of the equation then isolating the variable.

b= \frac{12}{x}+ \frac{72}{ x^{2} }-2+2a- \frac{4a}{x}+ \frac{ a^{2} }{x}- \frac{2a^{z} }{ x^{2} }

Hopefully i helped ^.^ Mark brainly if possible. Lol once again i saw the same question so why not answer it again!
 


3 0
3 years ago
A bus driver started her day with an empty bus. At her first stop she picked up
lidiya [134]

Answer:

12 people.

Step-by-step explanation:

Let's do this one at a time.

First stop:

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11 + 5 = 16.

16 - 7 = 9.

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9 + 5 = 14.

14 - 2 = 12.

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8 0
2 years ago
A stretched spring has a length of 12 inches when a weight of 2 lbs is attached to the spring. The same spring has a length of 1
Advocard [28]
The way I figured this one out was saying that if it takes 2lbs to stretch it to 12 inches and 5lbs to stretch to 18 inches that means that 3 additional pounds = 6 inches. Therefore, each additional pound is 2 inches. We know already that with 2 lbs it was 12 inches in length and we can also say that 2 lbs = 4 inches. So subtract 4 from 12 and you end up with the answer of 8 inches. 
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2 years ago
8 is 16% of what?<br> Complete the sentence
zalisa [80]

Answer:

50

Step-by-step explanation:

the answer is 50 becuz it is

3 0
2 years ago
Find the center and radius of the circle whose diameter has an endpoint at (-3, -4) and the origin.
Zina [86]

Given end points of diameter,

(x1,y1)=(-3,-4)

(x2,y2)=(0,0)

Now,

the equation of circle is,

(x-x1)(x-x2)+(y-y1)(y-y2)=0

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or, x^2 +3x +y^2 +4y =0

or, x^2 +y^2 +3x + 4y=0

which is in the form of x^2 +y^2 +2gx +2fy + c=0

where,

g=3/2

h=2

c=0

Now,

radius(r) =  \sqrt{ {g}^{2}  +  {f}^{2} - c  } \\  =  \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } +  {2}^{2}  - 0 }  \\  =  \sqrt{ \frac{9}{4}  + 4}  \\  =   \sqrt{ \frac{25}{4} }  \\  =  \frac{5}{2}

6 0
3 years ago
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