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stellarik [79]
3 years ago
7

Simplify: |6 хо" - Чx2" 16xon - 2X912​

Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

It looks like there aren't many great matches for your search

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What two same numbers that times up to 136
Mariulka [41]
11.6619037897 or 11.7 (rounded to one decimal)
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3 years ago
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Identify the relative maximum value of g(x) for the function shown below <br><br> g(x) = 2/ x^2 +3
Dahasolnce [82]

Answer:

The relative maximum value is \frac{2}{3}

Step-by-step explanation:

The given function is

g(x)=\frac{2}{x^2+3}

We differentiate to obtain;

g'(x)=-\frac{4x}{(x^2+3)^2}

At turning points g'(x)=-\frac{4x}{(x^2+3)^2}=0

\implies x=0

g''(x)=\frac{16x^2}{(x^2+3)^3}- \frac{4}{(x^2+3)^2}

We apply the second derivative test to obtain:

g''(0)=\frac{16(0)^2}{((0)^2+3)^3}- \frac{4}{((0)^2+3)^2}=-\frac{4}{9}

Since the second derivative is negative, there is a relative maximum at x=0.

We substitute x=0 into the original function to obtain the relative maximum value.

g(0)=\frac{2}{(0)^2+3}=\frac{2}{3}

7 0
3 years ago
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Can someone please help me with number 5
kolbaska11 [484]

Answer:3 to 2

Step-by-step explanation: 6:4 reduces to 3:2

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3 years ago
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$1,000,000 Question: Answer these algebra problems
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What I meant was, which ones do you need and could you take a picture in better lighting? I can't see it all the way.
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3 years ago
Which pair of complex numbers has a real-number product? (1 + 3i)(6i) (1 + 3i)(2 – 3i) (1 + 3i)(1 – 3i) (1 + 3i)(3i)
Kobotan [32]

Answer:

<h2>(1 + 3i)(1 – 3i) gives real number product</h2>

Step-by-step explanation:

Given the expressions

(1 + 3i)(6i) ,(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i), (1 + 3i)(3i)

From analysis one of the following pairs has real-number products

(1 + 3i)(2 -3i), (1 + 3i)(1 - 3i)

Performing operations on

(1 + 3i)(2 -3i)= 2-3i+6-6i^2 \\= 2-3i+6-6(-1) \\=2-3i+6+6 \\=14-3i

Performing operations on

(1 + 3i)(1 - 3i) \\= 1-3i+3i-9(i)^2 \\= 1+0-9(-1) \\= 1+9=10

6 0
3 years ago
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