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3 years ago

Anyone have the answer??

Chemistry

2 answers:

kakasveta [241]3 years ago

8 0

The answer is 1 and 2

liubo4ka [24]3 years ago

5 0

Answer:

It might be 2 and 3 but tell me if I'm wrong cause I'm not 100% sure

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Calculate the molar mass of Fe2(SO4)3. Then Calculate the mass of iron(III) sulfate of 4.05x10^23 formula units. Work must be sh

Talja [164]

Answer:

Molar mass: 399.9 g/mol

The mass of iron(III) sulfate is 269 grams.

Explanation:

First of all, you have to find the molar mass of Fe2(SO4)3.

So you find the molar first for each element

However, there are 2 iron atoms, 3 sulfur atoms, and 12 oxygen atoms.(Don't forget the 3 outside the parenthesis of SO4).

So you do this

So the final answer is 399.9 g/mol

Second of all, if you want to find the mass of Fe2(SO4)3, you have to convert from formula units to moles. After that, then you convert from moles to grams.

If you want to convert from molecules to molecules, you have to use Avogadro's number. Avogadro's number is 6.02 x 10^23. Then if you want to convert from moles to grams, you use the molar mass. We already know that the molar mass is 399.9 g/mol.

Therefore, now use dimensional analysis to show your work.

<h3>(4.05 x 10^23) formula units of Fe2(SO4)3 * 1 mol/ 6.02 x 10^23 formula units * 399.9 g/mol / mol</h3>

Formula units in the beginning and the moles will cancel out.

But we need to use significant figures with the least digits(which is 4.05) So we round to the nearest whole number.

So the final answer for the mass of iron(III) sulfate is 269 grams(don't forget the units).

Hope it helped!

5 0

3 years ago

How many moles of methane are in 7.31*10^25 molecules?

GrogVix [38]

<h3>Answer:</h3>

121 mol CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Organic</u>

Writing chemical compounds
Writing organic structures
Prefixes
Alkanes, Alkenes, Alkynes

<u>Atomic Structure</u>

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.31 × 10²⁵ molecules CH₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u /> $\displaystyle 7.31 \cdot 10^{25} \ molecules \ CH_4(\frac{1 \ mol \ CH_4}{6.022 \cdot 10^{23} \ molecules \ CH_4} ) = 121.388 \ mol \ CH_4$ <u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

121.388 mol CH₄ ≈ 121 mol CH₄

7 0

3 years ago

Phase change occurs in which of the following

olchik [2.2K]

When something changes state.

For example solid to a liquid

Liquid to a gas

5 0

3 years ago

Read 2 more answers

For the reaction represented by the equation 2KClO3 → 2KCl + 3O2, how many grams of potassium chlorate are required to produce 1

Vikentia [17]

The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams

<u><em>calculation</em></u>

2 KClO₃→ 2 KCl + 3O₂

Step 1: find the moles of O₂

moles = mass÷ molar mass

from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol

moles = 160 g÷ 32 g/mol = 5 moles

Step2 : use the mole ratio to determine the moles of KClO₃

from equation given KClO₃ : O₂ is 2:3

therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles

Step 3: find the mass of KClO₃

mass= moles x molar mass

from periodic table the molar mass of KClO₃

= 39 + 35.5 + (16 x3) =122.5 g/mol

mass = 3.333 moles x 122.5 g/mol =408.29 grams

7 0

3 years ago

Can you give me a Biography about Mendeleev's Periodic Table?

Alecsey [184]

Answer: Dmitri Mendeleev was a Russian chemist who lived from 1834 to 1907. He is considered to be the most important contributor to the development of the periodic table. His version of the periodic table organized elements into rows according to their atomic mass and into columns based on chemical and physical properties

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3 years ago