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3 years ago

How do you solve real world problems that involve multiple percents?

Chemistry

2 answers:

vlabodo [156]3 years ago

6 0

Answer:

Percentages are used widely and in many different areas. For example, discounts in shops, bank interest rates, rates of inflation and many statistics in the media are expressed as percentages. Percentages are important for understanding the financial aspects of everyday life.

Explanation:

V125BC [204]3 years ago

5 0

a calculator or be like me and ask otherslol

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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.85×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.17×10−4, what is the

kramer

Answer:

The equilibrium constant of the given reaction is 0.01351.

Explanation:

$PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)$

The equilibrium constant of the reaction = $K_3=1.85\times 10^{-10}$

$K_3=\frac{[Pb^{2+}][Cl^-]^2}{[PbCl_2]}$ ...[1]

$AgCl(aq)\rightleftharpoons Ag^{+}(aq)+Cl^-(aq)$

The equilibrium constant of the reaction = $K_4=1.17\times 10^{-4}$

$K_4=\frac{[Ag^+][Cl^-]}{[AgCl]}$ ..[2]

$[Cl^-]=\frac{K_4\times [AgCl]}{[Ag^+]}$

$PbCl_2(aq)+2Ag^+(aq)\rightleftharpoons 2AgCl(aq)+Pb^{2+}(aq)$

The expression of equilibrium constant of the creation is ;

$K=\frac{[AgCl]^2[Pb^{2}]}{[PbCl_2]][Ag^+]^2}$

Dividing [1] by [2]

$\frac{K_3}{K_4}=\frac{\frac{[Pb^{2+}][Cl^-]^2}{[PbCl_2]}}{\frac{[Ag^+][Cl^-]}{[AgCl]}}$

$\frac{K_3}{K_4}=\frac{[Pb^{2+}][Cl^-][AgCl]}{[PbCl_2][Ag^+]}$

Substituting the value of $[Cl^-]$ from [2] :

$\frac{K_3}{K_4}=\frac{[Pb^{2+}][AgCl]}{[PbCl_2][Ag^+]}\times \frac{K_4\times [AgCl]}{[Ag^+]}$

$\frac{K_3}{K_4}=K_4\times K$

$K=\frac{K_3}{(K_4)^2}=\frac{1.85\times 10^{-10}}{(1.17\times 10^{-4})^2}$

$K=0.01351$

The equilibrium constant of the given reaction is 0.01351.

3 0

3 years ago

a binary mixture is to be fed a continuous distillation column. calculate the minimum number of trays required to achieve a sepa

Taya2010 [7]

Answer:

minimum number of trays:

N = 7 trays

Explanation:

minimum number (N):

N = ( Log ( (Xd / ( 1 - Xd )) * (( 1 - Xb ) / Xb )) ) / Log α....Fenske's Eq. binary mixture

∴ α = 2.5

∴ Xd = 0.96.......molar fraction the distillate

∴ Xb = 0.04 .........molar fraction in the bottoms

⇒ N = ( Log ( ( 0.96 / ( 1 - 0.96 ) ) * ( ( 1 - 0.04 ) / 0.04 )) ) / Log ( 2.5 )

⇒ N = 6.94 ≅ 7 trays

3 0

3 years ago

Pls help this isn’t hard I’m just not sure about the answer this is also Science ATTENTION

fgiga [73]

The answer is probably c i guess

6 0

3 years ago

How are new kinds of matter formed in a chemial change?

shtirl [24]

Because the reactants react with each other and chemically react to produce a different product like with fire when it reacts with the wood it burns and the product left behind is a new different substance from the reactants in this case the product is ash

7 0

4 years ago

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An instrument used to separate cell parts according to density is the

grigory [225]

It’s a centrifuger there are many steps to this do I advise looking on the internet or i could explain if needed

7 0

4 years ago