Question

_______. In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to ________. 8.314 m3-Pa/mol-K 0.08206 atm L mol-1K-1 1.987 cal mol-1K-1 62.36 L torr mol-1K-1 none of the above

Answer 1

Answer:

$8.314\ \text{m}^3\text{Pa/mol K}$

Explanation:

Let us find the unit of the gas constant R from the ideal gas equation. We substitute the units of the quantities rearrange them and get the units of the gas constant.

P = Pressure = Pa

V = Volume = $\text{m}^3$

n = Moles = mol

T = Temperature = K

$PV=nRT\\\Rightarrow R=\dfrac{PV}{nT}\\\Rightarrow R=\dfrac{\text{Pa m}^3}{\text{mol K}}$

Here, $\text{Pa}$ is used so the gas constant value that must be used is $8.314\ \text{m}^3\text{Pa/mol K}$.