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marysya [2.9K]
3 years ago
11

find the weight of the same object on a planet where the gravitational attraction has been reduced to 1/10 of the earth pull sho

w all work
Chemistry
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

9.9Xkgms-¹

Explanation:

Let mass of object be xkg

Gravitational pull is 10m/s-1/10=99/10=9.9

9.9xkgms-¹

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The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e
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Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

           N_{2}O_{4} \rightarrow 2NO_{2}

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                    N_{2}O_{4} \rightarrow 2NO_{2}

Initial :               x                   0

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Equilibrium : (x - 0.1)             0.2

Now, expression for K_{p} of this reaction is as follows.

     K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

Putting the given values into the above formula as follows.

          K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}

                 2 = \frac{(0.2)^{2}}{(x - 0.1)}

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This means that P_{N_{2}O_{4}} = x = 0.12 atm.

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D. a reactant that is catalyzed by an enzyme

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um

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2 years ago
Write the net ionic equation for the precipitation of calcium sulfide from aqueous solution
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Answer:

Answer is Ca2+(aq)+S2-(aq)=>CaS(s)

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I hope it's helpful!

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