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2 years ago

Give the systematic name for the following compound

Chemistry

1 answer:

Zielflug [23.3K]2 years ago

8 0

Answer:

2,4–dimethylhexane.

Explanation:

To name the above compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name. In this case, the longest chain is carbon 6 i.e Hexane.

2. Identify and Locate the position of the substituent group attached. In this case, the substituent group attached is methyl i.e CH3 and it is at carbon 2 and 4.

3. Combine the above to get the name.

Therefore, the name of the compound is:

2,4–dimethylhexane.

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2 years ago

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

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2 years ago