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3 years ago

How many molecules are in 1 mol of sucrose (C12H22O11)?

Chemistry

1 answer:

charle [14.2K]3 years ago

3 0

Answer:

6.022 × 10²³ molecules of sucrose

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For one mole sucrose:

342.3 g of sucrose = 1 mole of sucrose = 6.022 × 10²³ molecules of sucrose

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This is when an organism like insects or plants become trapped in amber

BigorU [14]

thats very nice lol, things stuck in amber are very cool

5 0

2 years ago

Show your work including units in your answer. Calculate the molar mass of Li4OH

lorasvet [3.4K]

Empirical formula: Li4OH
Answer:
1 mole: 44.771 g
1 gram = 0.022 mole

Explanation:

Element: Li
Percentage by mass: 62.01%
Number of atoms: 4
Mass of atom;: 6.941

Element: O
Percentage by mass: 35.74%
Number of atoms: 1
Mass of atom: 15.9994

Element: H
Percentage by mass: 2.25%
Number of atoms: 1
Mass of atom: 1.00794

4 0

3 years ago

Picture shown! What is the melting point of this substance at 1 ATM of pressure?

Oksana_A [137]

Answer:

The melting point of this substance at 1 ATM of pressure is 110°.

5 0

2 years ago

What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:

Margarita [4]

Answer:

108.6 g

Explanation:

2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the PV=nRT formula to calculate the number of nitrogen moles:

P = 1.00 atm

V = 56.0 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 0 °C ⇒ 0 + 273.2 = 273.2 K

Inputting the data:

1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K

n = 2.5 mol

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

2.5 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.67 mol NaN₃

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

1.67 mol * 65 g/mol = 108.6 g

6 0

2 years ago

HURRRRRYYYYYYY!!!!!!!!!!!!!!!!!!!

Vladimir79 [104]

Answer:

Explanation:

What an interesting amusing question.

The formula for KE = 1/2 m v^2.

v implies that there is motion.

The answer you are looking for is the body of water that has 0 for v.

A cloud moves, so it is not the answer.

A hailstone moves until it hits the ground. I'm assuming it's either on it's way down or it is caught in some sort of updraft in a cumulonimbus cloud. So it has motion.

Same comment for a raindrop. It has a v until it hits the ground so I'm assuming it is not the answer.

I've never seen a puddle of water move. It can only evaporate. So of all your choices, this one (D) is likely the right answer.

4 0

3 years ago