Answer:
1) The gradient of a line perpendicular to AB.→ [-2}
2) The equation of the line perpendicular to AB and passing
through the midpoint of AB. →[y=-2x+6]
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In order for the parallelogram to be a square, x=?
2 answers:
Answer:
<h2>7°</h2>Step by step explanation
We know that the diagonals of a square bisects it's angles and every angles of square are 90°
m<BCD = 90°
m<BCA = m< DCA = 4x + 17
m<BCA + m<DCA = m <BCD
4x + 17 + 4x + 17 = 90
4x + 4x + 17 + 17 = 90
8x + 34 = 90
8x = 90 - 34
8x = 56
X = 56/8
x = 7
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