Part A
The small red arcs indicate that angles PQS and RQS are congruent.
13x - 1 = 2(6x + 4)
13x - 1 = 12x + 8
x = 9
m<PQR = 13x - 1 = 116
m<RQS = 6x + 4 = 6(9) + 4 = 58
m<PQS = 116 - 58 = 58
Part B
12^2 + (OH)^2 = 13^2
144 + (OH)^2 = 169
(OH)^2 = 25
OH = 5
r = OH = 5
Part C
WZ/ZY = WX/XY
24/12 = 30/XY
2 = 30/XY
2(XY) = 30
XY = 15
Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
This is called the leading term
Answer:
the answer is a b and d
Step-by-step explanation:
I took the quiz
Answer:
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Step-by-step explanation:
