Answer:
The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .
Explanation:
Given that,
Rate = 2940 rev/min
Amplitude = ±5.50 cm
(a). We need to calculate the magnitude of the maximum velocity
Using formula of maximum velocity
Where, A = amplitude
Put the value into the formula
(b). We need to calculate the maximum acceleration
Using formula of maximum acceleration
Hence, The the magnitude of the maximum velocity and acceleration are 16.93 m/s and .
I think maybe C. a light bulb. Hope this helps :)
Answer:
f1 / f2 = n2 / n1
Explanation:
To solve this problem, we should remember that the formula for index of refraction is defined as:
n = c / v
or
n v = c
Where,
n = index of refraction
c = speed of light
v = speed of light in the medium
Since speed of light is constant, then we can simply equate the materials 1 and 2:
n1 v1 = n2 v2
Where the speed of light in the medium (v) can be expressed as:
v = w * f
Where,
w = wavelength of light
f = frequency of light
Therefore substituting this back into the relating equation:
n1 w1 f1 = n1 w2 f1
Since it is given that the light is monochromatic, w1 = w2, this further simplifies the equation to:
n1 f1 = n2 f2
f1 / f2 = n2 / n1 (ANSWER)
To weaken and ruin the lungs and allowing them to shrivel other example would be chapped lips death or exhaustions
C)Wavelength
It has a low frequency electromagnetic radiation that's used to transmit information.