B b b b b b b bb bb bb b b b b b b b b b
The maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
<h3>
Maximum speed of the face</h3>
v = fλ
where;
- f is frequency of the wave
- λ is the wavelength
<h3>Angular speed of the wave</h3>
ω = 2πf
v(max) = ωA
v(max) = 2πfA
where;
- A is amplitude of the wave
v(max) = 2π(215)(50 x 10⁻⁹ m)
v(max) = 6.75 x 10⁻⁵ m/s
Thus, the maximum speed of the face is determined as 6.75 x 10⁻⁵ m/s.
Learn more about maximum speed here: brainly.com/question/4931057
#SPJ1
Answer:
48 seconds
Explanation:
Since S=d/t, plug in the known values and solve
0.25m/s=12m/t
0.25m/s*t=12m
t=12m/0.25m/s
t=48 seconds
Answer:
A: They produce a real image.
Explanation:
The images formed on the retina of the eye for a normal visibility must always be real.
Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.
- The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.
depending on the object the force pressing in on the object are equal with the quantity of the object.
