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baherus [9]
3 years ago
14

Whats the answer to this question show in the picture 2 questions

Physics
2 answers:
astraxan [27]3 years ago
3 0

1) D

2) I would say A, but not 100%, its the only one that makes sense tho

almond37 [142]3 years ago
3 0

The first one would be KE=0.5m(v to the 2nd power)

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Suppose the ring rotates once every 4.30 ss . If a rider's mass is 58.0 kgkg , with how much force does the ring push on her at
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Answer:

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Explanation:

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- N - m g = \dfrac{-mv^2}{R}

N + m g = \dfrac{mv^2}{R}

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The force exerted by the ring to push her is equal to 422.36 N.

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