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Alex Ar [27]
3 years ago
7

Please help me answer this question with breakdown on how you got the answer.

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

Anwer is 426.4.

Step-by-step explanation:

HOPE ITS HELP YOU.

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The radius is 10 units, and each layer is one unit high. What is the volume of the cylinder in cubed units?​
alexandr1967 [171]

Answer:

Volume of cylinder is 6285.71 square units.

Step-by-step explanation:

Given the radius of cylinder 10 units. The height is twice its radius. we have to find its volume.

r=10 units

⇒ Diameter, d = 20 units

Also given height is twice its radius.

⇒ Height=2(r)=2(10)=20 units

<h2><em><u>Volume of cylinder=πr^2h</u></em></h2>

= 22/7 × 100×20

=22/7 × 2000

= 44000/7

= 6285.71square units.

hence, volume of cylinder is 6285.71 square units.

6 0
2 years ago
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School guidelines require that there must be at least 2 chaperones for every 25 students going on a school trip. How many chaper
noname [10]
25 students got 2 chaperones
so 1 will get 2/25

and thus 8 will get 2/25×8 = 0.64 chaperone

but is it possible?? No chaperone can not be in decimal so at least 1 is required !!
3 0
3 years ago
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The express meal at a restaurant includes 1 soup, 1 pizza, and 1 dessert. There are 5 types of soups, 2 types of pizzas, and 3 t
bixtya [17]
B)10 is the right answer
4 0
3 years ago
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One 6 oz juice box has 90 calories. How many calories are there in 64 oz jug of the juice? Round to the nearest calorie.
Aleonysh [2.5K]

Answer:

960 calories for the 64 oz jug

Step-by-step explanation:

6 oz for 90 calories.

64 oz for ??? calories.

It's a ratio, 6:90

and            64:???

so  6 * 10 2/3 is 64.

so 90 * 10 2/3 is ???

960 is ???

5 0
3 years ago
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Determine whether the improper integral converges or diverges, and find the value of each that converges.
pantera1 [17]

Answer:

It diverges.

Step-by-step explanation:

We are given the integral: \int\limits^{-1}_{-\infty} \ln |x| dx

\int\limits^{-1}_{-\infty} \ln |x| dx=\int\limits^{-1}_{-\infty} \ln (-x) dx=\\\\= \lim_{t \to \infty} \int\limits^{-1}_{-t} \ln (-x) dx= \lim_{t \to \infty}( x(\ln \left(-x\right)-1))|^{-1}_{-t}=1-\infty=-\infty

So it is divergent.

7 0
4 years ago
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