Given:
Initial price of the stock=$43.85
Change for the first two days=+$2.70
Change for next two days=-$1.10
Last day=-$4.45
The objective is to find the price at the last day.
Let's take the price at final day as <em>x</em>.

Hence, the price of the stock at the last day is $42.6
Answer:
kora is 13
Step-by-step explanation:
venla is 5 years older than kora
18-5=13
Answer:

425 pounds or less can be added after the student and football player.
Step-by-step explanation:
let x = remaining weight
(note that >/= is greater than or equal to.)
800 - 280 - 95 >/= x
425 >/= x
5a - 10*3 = 45
5a - 30 = 45
5a = 45 + 30
5a = 75
a = 15
Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
<h3>Zeros of a function</h3>
The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.
In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.
In a quadratic function that has the form:
f(x)= ax² + bx + c
the zeros or roots are calculated by:

<h3>This case</h3>
The quadratic function is f(x) = x² + 4x +9
Being:
the zeros or roots are calculated as:



and



If the content of the root is negative, the root will have no solution within the set of real numbers. Then
has no solution.
Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
Learn more about the zeros of a quadratic function:
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