Answer: The numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>
Step-by-step explanation:
We know that , for critical value of F, degrees of freedom for numerator = k-1
and for denominator = n-k, where n= Total observations and k = number of independent variables.
Here, Numbers of independent variables(k) = 5
Total observations (n)= 123
So, Degrees of freedom for numerator = 5-1=4
Degrees of freedom for denominator =123-5= 118
Hence, the numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>
Answer:
A)14 Units is the answer for this question
but check it
Answer:
B
Step-by-step explanation:
Equation of line 1:
Choose two points : (-1, 0) & (0,2)
y -intercept = b = 2
y = mx+ 2
Plugin the values of the points ( -1 , 0) in the above equation
0 = -1m + 2
-2 = -m
m = 2
Equation of line 1 : y = 2x + 2
Equation of line 2:
(5,0) & (0,5)
y-intercept = b = 5
y = mx +b
y = mx + 5
Plugin the value of points (5 , 0) in the above equation
0 = 5m + 5
-5 = 5m
-5/5 = m
m = -1
Equation of line 2: y = -x + 5
Conclusion: 2x + 2 = -x + 5
