An arithmetic

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

Answer:

an = 7.5 - 5.5(n - 1).

Step-by-step explanation:

The common difference d = -5.5.

The first term is given as 7.5.

Explicit formula is

an = a1 + (n - 1)d

= 7.5 + (n - 1)-5.5

= 7.5 - 5.5(n - 1)

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stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

$\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2$

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

$\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24$

Point (-2,-24)

$\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6$

Point (0,-6)

$\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0$

Point (2,0)

$\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6$

Point (4,-6)

$\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24$

Point (6,-24)

The graph is shown in the image below

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3 years ago

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Simora [160]

$\ [cos(2\theta)]'=(2cos^2\theta-1)'=2(cos^2\theta)'-(1)'\\\\=2\cdot2cos\theta\cdot(-sin\theta)-0=-2\cdot2sin\theta cos\theta=\boxed{-2sin2\theta}\\\\Used:\\\ [f(x)-g(x)]'=f'(x)-g'(x)\\\{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\(cosx)'=-sinx\\sin2x=2sinxcosx$