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olga2289 [7]
4 years ago
11

Based on the given information, it is guaranteed that AC is congruent to BC.

Mathematics
2 answers:
AURORKA [14]4 years ago
7 0
Im not that good but i think its true
notka56 [123]4 years ago
3 0
True it seems to me!!!!
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10. If x = -2, y=-6 and z= 4, find the value of 4xy<br>Z​
Grace [21]

Answer:

192

Step-by-step explanation:

Given

4xyz ← substitute given values into expression

= 4 × - 2 × - 6 × 4 = - 8 × - 24 = 192

5 0
3 years ago
calcular el valor de la fuerza desconocida en cada gráfico, si el sistema esta en equilibrio (les pongo coronita :c ayuda porfaa
blondinia [14]

Answer:

7. F=24N

8. P=16N

Step-by-step explanation:

the sum of all forces will equals 0

8 0
3 years ago
If the circumference of a circle measures 8 pi cm, what is the area of the circle in terms of pi?
Effectus [21]

Answer:

803.84

Step-by-step explanation:

the formula for the area of a circle is A = π r2 which is pi times the radius squared.n in this case if the circumference is 8 cm then the radius would be half of the circumference which is 4. then you square 4 which is equal to 256. Then take 256 and multiply it by pi. 256 × 3.14 = 803.84. i hope this helped you.

8 0
3 years ago
Can absolute value be negative
emmasim [6.3K]
No, only the value of what you are finding the absolute value of can be a negative. Examples: |-2|=2 |2|=2
3 0
3 years ago
Factorize :3y²-54y+343​
arlik [135]

1 In general, given

a

x

2

+

b

x

+

c

ax

2

+bx+c, the factored form is:

a

(

x

−

−

b

+

b

2

−

4

a

c

2

a

)

(

x

−

−

b

−

b

2

−

4

a

c

2

a

)

a(x−

2a

−b+

b

2

−4ac

​

​

)(x−

2a

−b−

b

2

−4ac

​

​

)

2 In this case,

a

=

3

a=3,

b

=

−

54

b=−54 and

c

=

343

c=343.

3

(

y

−

54

+

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

(

y

−

54

−

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

3(y−

2×3

54+

(−54)

2

−4×3×343

​

​

)(y−

2×3

54−

(−54)

2

−4×3×343

​

​

)

3 Simplify.

3

(

y

−

54

+

20

3

ı

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

54+20

3

​



​

)(y−

6

54−20

3

​



​

)

4 Factor out the common term

2

2.

3

(

y

−

2

(

27

+

10

3

ı

)

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

2(27+10

3

​

)

​

)(y−

6

54−20

3

​



​

)

5 Simplify

2

(

27

+

10

3

ı

)

6

6

2(27+10

3

​

)

​

to

27

+

10

3

ı

3

3

27+10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

54

−

20

3

ı

6

)

3(y−

3

27+10

3

​



​

)(y−

6

54−20

3

​



​

)

6 Factor out the common term

2

2.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

2

(

27

−

10

3

ı

)

6

)

3(y−

3

27+10

3

​



​

)(y−

6

2(27−10

3

​

)

​

)

7 Simplify

2

(

27

−

10

3

ı

)

6

6

2(27−10

3

​

)

​

to

27

−

10

3

ı

3

3

27−10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

27

−

10

3

ı

3

)

3(y−

3

27+10

3

​



​

)(y−

3

27−10

3

​

I hope this help you

​

6 0
3 years ago
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