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The energy of a photon is given by
E = h × v
where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴
Substitute 'h' and 'v' into the formula we have
E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
Answer:
The answer is below.
Step-by-step explanation:
The GCF is 2z because it is the biggest number that can be factored out of both numbers. Also, since the 8z has no exponent, the GCF of 2z doesn't need one either.
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Dominio:
(−∞,∞),{x|x∈R}
Rango:
(−∞,∞),{y|y∈R}
12) 12, 8
12 - 8 = 4
12 + 8 = 20
Answer: 4 < x <span>< 20
13) 11, 3
11 - 3 = 8
11 + 3 = 14
Answer: 8 </span>< x <span>< 14
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