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IrinaK [193]
2 years ago
11

1. A booklet has 12 pages with the following numbers of :

Mathematics
1 answer:
blagie [28]2 years ago
7 0

Answer:

C

Step-by-step explanation:

THe mean deviation is the sum of all the differences of the values from the mean and then we divide by the number of values in the data set.

First, lets find the mean (sum of all the numbers divided by number of numbers):

Mean = (271+354+296+301+333+326+285+298+327+316+287+314)/12 = 309

Now, the mean deviation:

|(271-309+(354-309+(296-309+.....(314-309))|/12 = <u>19.33</u>

<u>The mean absolute deviation (MAD) is equal to 19.33</u>

<u>Correct answer is C</u>

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Step-by-step explanation:

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0.3x +y = 7 represents a linear function
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Yes it represents a linear function.
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I NEED HELP ASAPPPP<br> In square YOLA , RL=5x+28 and RO=8x-11 find the measure of line segment RY
tresset_1 [31]

Answer:

RL=5x+28 and

RO=8X-11

diagonal of square bisect equally the side

:.5x+28=8x-11

11+28=8x-5x

39=3x

x=39/3=13

RY=RL=5x+28=5×13+28=93If the answer is 93, move to S

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2 years ago
I can re-write an equation from Standard Form to Slope-Intercept Form. 4x + 3y = -6​
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2 years ago
In order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral r
LekaFEV [45]

Answer:

Yes, there is evidence that more than 50% of likely voters will likely vote for the incumbent.

Step-by-step explanation:

We are given that in order to estimate the proportion of all likely voters who will likely vote for the incumbent in the upcoming city’s mayoral race, a random sample of 267 likely voters is taken, finding that 65% state they will likely vote for the incumbent.​

The polling agency wishes to test whether there is evidence that more than 50% of likely voters will likely vote for the incumbent.

<em>Let p = proportion of  voters who will likely vote for the incumbent</em>

SO, <u>Null Hypothesis</u>, H_0 : p \leq 50%   {means that less than or equal to 50% of likely voters will likely vote for the incumbent}

<u>Alternate Hypothesis</u>, H_A : p > 50%   {means that more than 50% of likely voters will likely vote for the incumbent}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

             T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where,  \hat p = sample proportion of voters who will likely vote for the incumbent in a sample of 267 voters = 65% or 0.65

            n = sample of voters = 267

So, <em><u>test statistics</u></em>  =   \frac{0.65-0.50}{{\sqrt{\frac{0.65(1-0.65)}{267} } } } }

                               =  5.139

<em>Since in the question we are not given the level of significance so we assume it to be 5%. Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the more than 50% of likely voters will likely vote for the incumbent. The strength of the evidence is 95%.

3 0
3 years ago
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