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3 years ago

Estimate how much farther sound travels through stone in 17 seconds than through a aluminum in the same time

Mathematics

1 answer:

aev [14]3 years ago

6 0

Sound travels 10200m farther through stone in 17 seconds than through aluminium

Speed of sound in aluminium = 3100 m/s

The speed of sound in stone = 3700 m/s

Time taken = 17 minutes

Distance traveled = Speed x Time

Distance traveled by sound in aluminium in 17 seconds = 3100 x 17

Distance traveled by sound in aluminium in 17 seconds = 52700 m

Distance traveled by sound in stone in 17 seconds = 3700 x 17

Distance traveled by sound in stone in 17 seconds = 62900 m

Difference in the distance traveled = 62900 - 52700

Difference in the distance traveled = 10200 m

Sound travels 10200m farther through stone in 17 seconds than through aluminium

Learn more here: brainly.com/question/13096122

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A stadium has 54,000 seats.Seats sell for 30$ in section A,$24 in section B, and $18 in section C.The number of seats in section

PilotLPTM [1.2K]

Answer:

46160

Step-by-step explanation:

Total price of seats A = 1384800÷2=692400

seats in section A=692400÷30=23080

seats in section B = 23080÷2=11520

seats in section C=23080÷2=11520

Totals seats in the stadium=23080 +11520 +11520 = 46160

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3 years ago

What fraction of 5 liter is 1500 ml

Andreas93 [3]

I think the answer is 1.5/5

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3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

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3 years ago

How many combinations with 3 numbers 0-9?

dusya [7]

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2nd number can be 0-9 = 10 numbers

3rd number can be 0-9 = 10 numbers

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3 years ago

To pass a test 36% marks are needed out of maximum a student gets 123 marks and is declared failed by 39 marks what are maximum

IgorLugansk [536]

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You would then divide 162 by .36 (.36 is equivalent to 36%). This would result in a maximum of 450 marks.

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