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lidiya [134]
2 years ago
5

Find the value of the variable 125

Mathematics
1 answer:
Alexxx [7]2 years ago
8 0
Answer: 55

The angles that measures 125 and y make a linear pair (equal 180)

So you just do 180-125 to get y
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What are three rational numbers between 0.2 and 0.3 (one must be a fraction)?
sveta [45]
It would be 2/5 but the numbers between is 2/10 and 3/10
4 0
3 years ago
Read 2 more answers
Can someone try doing this plz
Svetach [21]

Answer:

F

Step-by-step explanation:

Your welcome my guy :D

5 0
2 years ago
Read 2 more answers
What are the answers
dlinn [17]

Answer:

See below

Step-by-step explanation:

The ratio of the secants is the same when set up as full length to external length.

Formula

MN/LN = QN/PN

Givens

LN = 22 + 14 = 36

MN = 14

PN = 32

QN = x

Solution

14/36 = x / (32)  Multiply both sides by 32

14*32 / 36 = x    Combine 14 and 32

448/36 = x         Divide by 36 and switch

x = 12.4

Answers

PN (External) = 13 is the closest answer

Length LN = 36

6 0
3 years ago
Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,
melamori03 [73]

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

8 0
3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
2 years ago
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