3.
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$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer: 0.0885
Step-by-step explanation:
Given : According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest.
i.e. p= 0.16
Sample size : n= 154
Now, the probability that more than 20% of this sample is comprised of female employees is given by :-
[∵ ]
[Using the standard z-value table]
Hence, the required probability = 0.0885