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ra1l [238]
2 years ago
13

3.

Mathematics
1 answer:
Fudgin [204]2 years ago
6 0

40% means "40 out of 100"

    40 ÷ 100 = 0.40

So, 40% = 0.40 as a decimal

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PLS HELP If g(n) varies inversely with n and g(n) = 6 when n = 2, find the value of n when g(n) = 1.5.
rjkz [21]

Answer:

g(2)=1.5. Which would be three.

Step-by-step explanation:

You would just plug in n=2 into the equation and then divide it out.


4 0
2 years ago
Larry buys a tent that is on sale for 25% off the original price. The original price is $80 more than the sale price. What is th
myrzilka [38]

Answer:

The original price of the tent = $320

Step-by-step explanation:

Let the original price be =$ x

Discount offered  = 25% of the orignal price = \frac{25}{100}\times x=0.25\times x =\$ 0.25x

Original price is $80 more than sale price

Discount = Original price - Sale price = $80

So, we have

0.25x=80

We need to solve for x to find original price

Dividing both sides by 0.25

\frac{0.25}{0.25}x=\frac{80}{0.25}\\x=\$320

∴ The original price of the tent = $320

3 0
3 years ago
What is the slope formula?
Ksivusya [100]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which graph represents the function y=3x^2+2
alexira [117]
None, you wrote a different function than the one in the picture.

The answer to the picture is the last graph 
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3 years ago
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There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the
Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = <u>14.13.12!</u> = <u>14.13 </u>= 91

           12! 2!            2    

C₁₆,₂ = <u>16.15.14!</u> = <u>16.15 </u>= 120

           14! 2!            2    

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = <u>14.13.12.11.10!</u> = <u>14.13.12.11 </u>= 1001

                  10! 4!               4.3.2.1    

C₁₆,₄ = <u>16.15.14.13.12!</u> = <u>16.15.14.13 </u>= 1820

                  12! 4!               4.3.2.1    

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

7 0
3 years ago
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