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erik [133]
3 years ago
5

I need help really quick

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

15

Step-by-step explanation:

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In the diagram, m∠COE = 55°. If m∠2 = 2x and m∠3 = x+10, what is the measure of angle 2?
hram777 [196]
So here is how we are going to get the measure of angle 2. 
Since given that angle COE measures 55°, we will equate <span>m∠2 = 2x and m∠3 = x+10 with 55. So, 55 = 2x + x + 10
55 = 3x + 10
55-10 = 3x
45 = 3x << divide both sides by 3 and the result is 
15 = x
So now that we know x, we can now solve for angle 2.
</span>m∠2 = 2x
m∠2 = 2(15)
m∠2 = 30<span>°
I hope that this is the answer that you are looking for. </span>
7 0
3 years ago
Read 2 more answers
If f(x)=1/9x-2 what is f^-1(x)
Katarina [22]

Answer:

Uhh

Step-by-step explanation:

Jhbnhhnmjh

5 0
4 years ago
In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.​
mel-nik [20]

\large\underline{\sf{Solution-}}

Given that,

<em>In triangle ABC</em>

\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: -  -  - (1) }

\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \:  -  -  - (2)}

We know,

Sum of all interior angles of a triangle is supplementary.

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }

<u>On adding equation (1) and (2), we get </u>

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree  + 150 \degree \:}

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree  \:}

\purple{\rm :\longmapsto\:\angle B = 95\degree  \:}

On substituting the value in equation (1) and (2), we get

\purple{\rm :\longmapsto\:\angle A + 95\degree  = 125\degree }

\purple{\rm :\longmapsto\:\angle A =  125\degree - 95\degree  }

\purple{\rm :\longmapsto\:\angle A =  30\degree  }

Also, from equation (2), we get

\purple{\rm :\longmapsto\:95\degree  + \angle C = 150\degree }

\purple{\rm :\longmapsto\:\angle C = 150\degree  - 95\degree }

\purple{\rm :\longmapsto\:\angle C = 55\degree }

Hence,

\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree }  \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}

3 0
3 years ago
Read 2 more answers
Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to
jekas [21]
Hi there

(a) the total installment price
93×15=1,395

(b) the carrying charges
1,395−1,250=145

(c) the number of months needed to save the money at the monthly rate to buy the item for its cash price.
1,250÷93=13

Good luck!
6 0
4 years ago
Follow all directions in the problem below.
kirill115 [55]

Answer: 110 test were purchased

Step-by-step explanation:

Set P = number of packets of 10 test

Total cost = $30 + $11 x P = $151

$11xP = $151 - $30 = $121

P = $121/$11 = 11 packets were purchased

Test purchased = 11packets x 10 test/packet = 110 test were purchased

Answer: 110 test were purchased

<h3><em>Spymore</em></h3>
4 0
3 years ago
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