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2 years ago

10

what is the area of a figure what is the area of a figure with a 16 inch base a 10 inch base and a height of 8 in on the left an

d 6in on the right

1 answer:

tensa zangetsu [6.8K]2 years ago

3 0

So I’m thinking of this as two triangles. So I would do 16x8/2 which equals 64 and 10x6/2 which equals 30. So my guess is that the area is 94in^2. Hope this helps you out!

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ad-work [718]

478 955 520 is your answer hope this helps

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3 years ago

An airplane flew at an average speed of 376 miles per hour for 3 3/4 hours. How far did the plane fly?

Sav [38]

The distance is 1410 miles.
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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Match each expression with its simplified form. Tiles 3a5 − (-a5) 6a7

fredd [130]

3a^5 - (-a^5) = 3a^5 + a^5 = 4a^5

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3 years ago

Read 2 more answers

Rewrite as a quotient of two base - 9 logarithms. write your answer in simplest form log 17 =<br>

4vir4ik [10]

Answer:

$\frac{log_{9}17 }{log_{9}10 }$

Step-by-step explanation:

Using the change of base rule for logarithms

$log_{b}$ x = $\frac{log_{c}x }{log_{c}b }$ ( where c is the new base )

Given

log 17 , that is $log_{10}$ 17 , then

$log_{10}$ 17 = $\frac{log_{9}17 }{log_{9}10 }$

8 0

3 years ago

Find angle A and angle B..

ExtremeBDS [4]

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

$\tt{\angle{c}=110°}$

and,

$\tt{BC=AC}$

⠀⠀⠀⠀

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

☆Find the $\angle{B} ~and~\angle{A}$

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Here,

BC =AC

so,

⠀⠀⠀

$\angle{A}=\angle{B}$

we know that,

$\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}$

But $\angle{C}=110°$ (Ģìvéñ)

so..

$\angle{A}+\angle{B}+110°=180°$

$\angle{A}+\angle{A}+110°=180°$

$\because{\angle{A}=\angle{B} }$

$2\angle{A}=180°-110°$

$2\angle{A}=70°$

$\angle{A}=\dfrac{70°}{2}$

$\boxed{\orange{\angle{A}=35°}}$

But...

$\angle{A}=\angle{B}$

soo,

$\boxed{\orange{\angle{B}=35°}}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

⠀⠀⠀⠀

$\boxed{\green{\angle{A}=35°}}$

$\boxed{\green{\angle{B}=35°}}$

7 0

3 years ago