All categories

3 years ago

There are 225 calories in 5 candies. How many calories are in 3 candies?

Mathematics

2 answers:

Eddi Din [679]3 years ago

7 0

Answer:

135 calories in 3 candies

wel3 years ago

5 0

135 calories i think

You might be interested in

The vertices of AMNO are M (1,3), N (4,9), and O (7,3). The vertices of APQR are P (3,0), Q (4,2), and R (5,0) Which conclusion

Pavel [41]

Answer:

the correct answer should be C

Step-by-step explanation:

hope this helps you

3 0

3 years ago

If gas prices are now $3.75 and they were up 10% from 6 months ago, how much were gas prices 6 months ago?

Hatshy [7]

Given

gas prices are now $3.75 and it up 10% from 6 months ago.

Find out how much were gas prices 6 months ago.

To proof

gas prices now = $3.75

let the gas price 6 month ago = x

gas price now is rise up 10% from 6 months ago

First write 10% in simpler form

$= \frac{10}{100}$

= 0.1

Now the equation becomes

0.1x + x = 3.75

1.1x = 3.75

$x =\frac{3.75}{1.1}$

x = 3.41 (approx)

Thus gas prices 6 months ago be $ 3.41 (approx )

Hence proved

7 0

3 years ago

Let U={q, r, s, t, u, V, W, X, Y, Z},

trapecia [35]

Answer:

Ooh is theis unions I did it but

3 0

2 years ago

Kayra and Mycho sell flowers on weekends to earn extra money.For every 2 flowers that Kayra sells,Mycho sells 5. If Kayra sold 6

andreyandreev [35.5K]

Answer:

We know that:

For every two flowers that Kayra sells, Mycho sells 5.

Now, in the question we have:

"If Kayra sold 6 newspapers, how many did Mycho sell?"

There is no information about newspapers, so we can't answer anything.

If we had something like:

"If Kayra sold 6 flowers, how many did Mycho sell?"

Well, in this case, we remember that for every 2 flowers that Kayra sells, Mycho sells 5, then the first thing we need to do is count how many groups of 2 flowers we have in 6 flowers, this is:

6/2 = 3 groups.

And for each one of these, Mycho will sell 5 flowers, then the total number of flowers that Mycho sold is:

3*5 = 15 flowers.

5 0

3 years ago

Use the dot product to determine whether the vectors are parallel, orthogonal, or neither. v = (sqrt)2j, w = 4i

svetoff [14.1K]

Hello,

As $\vec{i}*\vec{j}=0\\
\vec{v}*\vec{w}=\sqrt{2}*\vec{i}*4*\vec{j}=4*\sqrt{2}*0=0$
Vectors are orthogonal.

4 0

4 years ago

Read 2 more answers