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postnew [5]
3 years ago
8

There are 225 calories in 5 candies. How many calories are in 3 candies?

Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0

Answer:

135 calories in 3 candies

wel3 years ago
5 0
135 calories i think
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Find x on this special right triangle
Vinil7 [7]

Answer:

x=9.79

Step-by-step explanation:

firstly find the hypotenuse of the first triangle

sin45=12/h

sin45h/sin45=12/sin 45

h=16.9

after finding the hypotenuse you can then use it to find x by using tan

tan60=16.9/x

tan60x/tan60=16.9/tan60

x=9.79

I hope this helps!!

3 0
3 years ago
What is the equation to (-3,1) and (0,-8)
puteri [66]
The change in x between the two is 3 and the change in y is -9. 
Divide -9 by 3 to get -3 using the rise over run slope formula.  
The equation is y = -8 + -3x because the -8 in the second set of coordinates is the y-intercept of the equation. 
Hope this helps!
4 0
3 years ago
a friend is having trouble with exponents and asks you to review some worked probelems look over the problems and correct any mi
Stella [2.4K]

We have the following expression:

2x^2y\cdot3x^5y^2

By combining similar terms, we get

2\cdot3\cdot x^2\cdot x^5\cdot y\cdot y^2

now, 2 times 3 is 6 and to add exponents, both the exponents and variables should be alike:

x^2\cdot x^5=x^{2+5}=x^7

Similarly,

y\cdot y^2=y^{1+2}=y^3

Therefore, the answer is

6x^7y^3

4 0
1 year ago
Q + 5/9= 1/6 from big ideas mathbook
Alika [10]
9We have such eqation
Q+ \frac{5}{9} = \frac{1}{6}    /*9   (multiply both sides by 9)
9Q+5=\frac{9}{6}    /-5 both sides
9Q=\frac{9}{6}- 5
9Q=\frac{9}{6}- \frac{5*6}{6}
9Q=\frac{9-30}{6}
9Q=-\frac{21}{6}        /:9 divide both sides by 9
Q=-\frac{21}{6}:9
Q\frac{21}{6*9} =- \frac{21}{54}=[tex] \frac{7}{18} - its the answer
6 0
3 years ago
Read 2 more answers
The equation 2x² + 2y2 – 8x - 12y + 16 = 0 defines a circle.
mixas84 [53]

Answer:

  C, E

Step-by-step explanation:

Here, we want to change the equation of a circle from general form to standard form. This is done by making the leading coefficients 1, completing the squares, and then rewriting the equation in standard form.

The leading coefficients of the given equation are 2, so we first want to divide by 2. This gives ...

  x² +y² -4x -6y +8 = 0

Subtracting 8 puts us in better position to complete the squares.

  x² +y² -4x -6y = -8

Now, we can add the squares of half the coefficients of the linear terms.

  (x² -4x +4) +(y² -6x +9) = -8 +13 . . . . . . matches C

And we can simplify this to the standard form equation:

  (x -2)² +(y -3)² = 5 . . . . . matches E

3 0
2 years ago
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