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2 years ago

Write a quadratic function in vertex form whose graph has the vertex (-3,5) and passes through the point (0,-14)

Mathematics

1 answer:

dsp732 years ago

5 0

Answer:

f(x) = -19/9(x + 3)² + 5

Step-by-step explanation:

Given the vertex, (-3, 5) and the point, (0, 14):

Use the following quadratic equation formula in vertex form:

f(x) = a(x - h)² + k

where:

(h, k) = vertex

a = determines whether the graph opens up or down, and makes the graph wide or narrow.

h = determines how far left or right the parent function is translated.

k = determines how far up or down the parent function is translated.

Plug in the values of the vertex, (-3, 5) and the given point, (0, 14) to solve for a:

f(x) = a(x - h)² + k

14 = a(0 + 3)² + 5

14 = a(3)² + 5

14 = a(9) + 5

Subtract 5 from both sides:

-14 - 5 = 9a

-19 = 9a

Divide both sides by 9 to solve for a:

-19/9 = 9a/9

-19/9 = a

Therefore, the quadratic function in vertex form is:

f(x) = -19/9(x + 3)² + 5

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

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2 years ago

The length of the Earth’s equator is about 40,000 km, and the Earth’s diameter is 8/25 the length of the equator. What is the di

o-na [289]

Answer:

See Below:

Step-by-step explanation:

40,000*8/25= the diameter, because the diameter is 8/25 of the equator which is 40000

Diameter= 40,000*8/25

Diameter= 12,800 km

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3 years ago

1. Let C be between D and E. Use the Segment addition Postulate to solve for v.

AURORKA [14]

By applying the segment addition postulate, the value of v = 7

According to the Segment Addition Postulate, it holds that if point C is between points D and E, therefore:

DC + CE = DE

Given that:

$DC = 2v-15\\\\CE = 3v-8\\\\DE = 27$

Therefore, by substitution, we will have the following equation:

$(2v-15) + (3v-8) = 27$

Open the bracket and solve for the value of v.

$2v-15 + 3v-8 = 27$

Add like terms

$5v - 23 = 27$

Add 23 to both sides

$5v - 23+ 23 = 27 + 23\\\\5v = 50$

Divide both sides by 5

v = 10

Therefore, using the segment addition postulate, the value of v = 10

Learn more about the segment addition postulate here:

brainly.com/question/1721582

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3x-4y=16 and 5x+2y=44 using elimination strategy and comparing strategy

chubhunter [2.5K]

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3 years ago

An airplane has a wingspan of 20 feet and a length of 15 feet. If the model of this airplane has a wingspan of 8 inches, what is

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Answer:

The length of the model is 6 inches.

Step-by-step explanation:

The wingspan of the airplane and length of the airplane are a ratio of 4:3

The model is also supposed to be 4:3.

4:3 x 2 = 8:6

Or, 20x12=240

240/8=30

15x12=180

180/30=6.

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2 years ago

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