Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
Answer:
80 and B is 96
Step-by-step explanation:
1920 ÷ 24 = 80
1920 ÷ 20 = 96
puedes comprobarlo en la calculadora
lo siento si es incorrecto
eso es lo que entendí
Answer:
Step-by-step explanation:
<u>Solving in steps</u>
- 7^-1/7^2 =
- 7^-1 × 7^-2 =
- 7^(-1 - 2) =
- 7^-3
