There's a total of 3 colors, the percent will add up to 100%
100%-50%(red)= 50%
50%-10%(blue)=40%
There is a 40% chance it will land on green
I think it’s hydroxybutanal
Answer: The linkages in starch and triglycerides resulting from condensation reactions is glycosidic bonds in starch and ester bonds in triglycerides
<span>A) 2NaOH -> 2Na + O2 + H2
is not correct since Na is unstable
B) 2NaOH -> 2Na + H2O + 1/2O2
is not correct since Na is unstable
C) 2NaOH -> Na2O + H2O
is correct since N2O is stable
D) 2NaOH -> 2Na + H2O2
is not correct since Na is unstable</span>
Answer:
0.74 grams of methane
Explanation:
The balanced equation of the combustion reaction of methane with oxygen is:
it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.
firstly, we need to calculate the number of moles of both
for CH₄:
number of moles = mass / molar mass = (3.00 g) / (16.00 g/mol) = 0.1875 mol.
for O₂:
number of moles = mass / molar mass = (9.00 g) / (32.00 g/mol) = 0.2812 mol.
- it is clear that O₂ is the limiting reactant and methane will leftover.
using cross multiplication
1 mol of CH₄ needs → 2 mol of O₂
??? mol of CH₄ needs → 0.2812 mol of O₂
∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol
so 0.14 mol will react and the remaining CH₄
mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol
now we convert moles into grams
mass of CH₄ left over = no. of mol of CH₄ left over * molar mass
= 0.0469 mol * 16 g/mol = 0.7504 g
So, the right choice is 0.74 grams of methane
