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son4ous [18]
3 years ago
13

Which of the following decomposition reactions is/are correct?

Chemistry
2 answers:
qwelly [4]3 years ago
7 0
<span>A) 2NaOH -> 2Na + O2 + H2
is not correct since Na is unstable

B) 2NaOH -> 2Na + H2O + 1/2O2
is not correct since Na is unstable

C) 2NaOH -> Na2O + H2O
is correct since N2O is stable

D) 2NaOH -> 2Na + H2O2
is not correct since Na is unstable</span>
maxonik [38]3 years ago
5 0

<u>Answer:</u> The correct statement is only reaction C is correct.

<u>Explanation:</u>

Decomposition reaction is defined as the reaction in which one large compound breaks down into smaller compounds.

NaOH is a base known as sodium hydroxide. The decomposition reaction for sodium hydroxide follow the equation:

2NaOH\rightarrow Na_2O+H_2O

By Stoichiometry of the reaction:

2 moles of sodium hydroxide decomposes into 1 mole of sodium oxide and 1 mole of water.

Hence, the correct statement is only reaction C is correct.

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Which of the following compounds is a molecule?
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What is the atomic mass of OsO4
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Answer:

254.23 g/mol

Explanation:

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For a tablet containing 500. mg of vitamin C, calculate how many ml of 0.095 M NaOH is required to reach the equivalence point.
Gala2k [10]

Answer:

mL of NaOH required =29.9mL

Explanation:

Let us calculate the moles of vitamin C in the tablet:

The molar mass of Vitamin C is 176.14 g/mole

moles=\frac{mass}{molarmass}=\frac{500mg}{176.14}=\frac{0.5}{176.14}=0.0028

Thus we need same number of moles of NaOH to reach the equivalence point.

For NaOH solution:

moles=MolarityXvolume=0.095Xvolume

0.00283=0.095Xvolume

volume=0.0299L=29.9mL

7 0
4 years ago
the force of a bag of potatoes on a vegetable stand is 22.25 n down. what is the force of the vegetable stand in the bag of pota
tatuchka [14]
22.25 upwards because at equlibrium
8 0
3 years ago
What mass of Fe(OH)3 will be obtained when 100. mL of 0.240 M FeCl3 is mixed with 200. mL of 0.182 M NaOH?
ratelena [41]

Answer:

648.68 mg

Explanation:

The reaction that takes place is:

  • FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

First we<u> calculate how many moles of each reactant were added</u>, using the <em>given volumes and concentrations</em>:

  • FeCl₃ ⇒ 100 mL * 0.240 M = 24 mmol FeCl₃
  • NaOH ⇒ 100 mL * 0.182 M = 18.2 mmol NaOH

24 mmol of FeCl₃ would react completely with (24 * 3) 72 mmol of NaOH. There are not as many NaOH mmoles, so NaOH is the limiting reactant.

Now we <u>calculate how many moles of Fe(OH)₃ are formed</u>, using the <em>moles of the limiting reactant</em>:

  • 18.2 mmol NaOH * \frac{1mmolFe(OH)_3}{3mmolNaOH} = 6.07 mmol Fe(OH)₃

Finally we <u>convert 6.07 mmol Fe(OH)₃ to grams</u>, using its<em> molar mass</em>:

  • 6.07 mmol Fe(OH)₃ * 106.867 mg/mmol = 648.68 mg
7 0
3 years ago
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