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Sloan [31]
3 years ago
15

8. A student filled a graduated cylinder with water and read the meniscus at 25.8 mL. The student

Chemistry
1 answer:
fomenos3 years ago
5 0

Answer:

<h2>30.2 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

volume = final volume of water - initial volume of water

From the question

volume = 35.9 ml - 25.8 ml = 10.1 mL

We have

mass = 2.99 × 10.1 = 30.199 g

We have the final answer as

<h3>30.2 g</h3>

Hope this helps you

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You can use Le Chatelier's Principle to describe the equilibrium shift.

Le Chaterlier's Principle states that: "<span>If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change."

Thus, if you heat up the reaction, the equilibrium shift favors the endothermic reaction. If you increase pressure (if gases are involved), the shift favors the reaction that produces less gaseous products (to counteract pressure) and so on.</span>
8 0
3 years ago
To what volume would you need to dilute 200 mL of a 5.85M solution of Ca(OH)2 to make it a 1.95M solution?
Blizzard [7]

Answer: 600 mL

Explanation:

Given that;

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8 0
3 years ago
How many orbitals are in the f sublevel?
lord [1]

Answer:

7 orbitals

Explanation:

An f sublevel has 7 orbitals

7 0
3 years ago
In this reaction, what is the substance oxidized? zn(s) + 2 hcl(aq) → zncl2(aq) + h2(g) zinc chloride chlorine hydrogen zn oxyge
Zarrin [17]
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g) 
Oxidation means lose of electrons and increase of positive charge so the part which oxidized in this equation is Zn(s) because it converted to Zn²⁺ (i.e. lost two electrons) 
7 0
3 years ago
Read 2 more answers
HC]A laboratory experiment requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M
andreyandreev [35.5K]

The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.

3 0
3 years ago
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