Answer:
1.429 g of N₂
Explanation:
The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:
- N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆ 2NH₃ ₍g₎
One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.
We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.
no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol
and the actual yield is 98% , then the theoretical number of moles that would be produced are:
- percent yield = (actual yield / theoretical yield) × 100
98 = (0.1 mol / theoretical yield) × 100
theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol
using cross multiplication
1 mol of N₂ → 2 mol of NH₃.
?? mol of N₂ → 0.102 mol of NH₃.
no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol
Last step is to convert the moles back to grams using:
mass = (no of moles of N₂ * molar mass of N₂)
= (0.051 mol * 28 g/mol) = 1.429 g
, and
.