All categories

4 years ago

A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.

Chemistry

1 answer:

daser333 [38]4 years ago

5 0

Answer:

1.429 g of N₂

Explanation:

The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:

N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆ 2NH₃ ₍g₎

One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.

We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.

no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol

and the actual yield is 98% , then the theoretical number of moles that would be produced are:

percent yield = (actual yield / theoretical yield) × 100

98 = (0.1 mol / theoretical yield) × 100

theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol

using cross multiplication

1 mol of N₂ → 2 mol of NH₃.

?? mol of N₂ → 0.102 mol of NH₃.

no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol

Last step is to convert the moles back to grams using:

mass = (no of moles of N₂ * molar mass of N₂)

= (0.051 mol * 28 g/mol) = 1.429 g

You might be interested in

Calculate the quantity of energy produced per gram of U-235 (atomic mass = 235.043922 amu) for the neutron-induced fission of U-

Alexus [3.1K]

Answer:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu; atomic mass of U-235= 235.043922 amu

Therefore:

delta(m)= (143.9385 + 89.907738) - (235.043922) = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of energy released

Explanation:

To calculate the amount of energy produced per gram from Uranium- 235 we call on the formula:

delta(m)= mass of the products - mass of reactants

Given the atomic mass of Xe-144 = 143.9385 amu; atomic mass of Sr-90= 89.907738 amu; atomic mass of U-235= 235.043922 amu

Therefore:

delta(m)= (143.9385 + 89.907738) - (235.043922) = -1.197682 amu

Recall that to calculate energy in joules, we use the formula:

Energy = mc^2

Therefore: Energy = (-1.197582/6.022 x 10^26)kg x (3 x 10^8 m/s)^2

= -1.7898104 x 10^-10 J

= (-1.7898104 x 10^-10 x 6.022 x 10^23/235.043922)

= -4.586 x 10^11 J per gram of energy released

7 0

4 years ago

If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5

aivan3 [116]

If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.3% isotope C (mass number 22), the atomic weight of the element measured from the sample will be greater than 21 amu.

To calculate the average atomic mass, multiply the fraction through the mass number for every isotope, then add them together. Whenever we do mass calculations concerning elements or compounds (combos of elements), we usually use average atomic loads.

For instance, carbon-14 is a radioactive isotope of carbon that has six protons and 8 neutrons in its nucleus. We name it carbon-14 because the overall range of protons and neutrons within the nucleus also called the mass number, provides up to fourteen (6+8=14).

Together, the quantity of protons and the range of neutrons determine an detail's mass variety. Due to the fact, that an element's isotopes have barely unique mass numbers, the atomic mass is calculated by obtaining the suggested mass numbers for its isotopes.

Learn more about atomic mass here brainly.com/question/1358482

#SPJ4

3 0

2 years ago

Why does decreasing the volume of gas cause the pressure to increase if temperature is constant

Yuri [45]

There's less space, causing the air particles to collide with the walls of the container more frequently. Pressure is that energy caused by molecules striking a surface. Thus, compacting air molecules leads to higher pressure.

5 0

3 years ago

When 16 g of methane (CH4) and 32 g of oxygen (O2) reacted to produce carbon dioxide and water, 11 g of carbon dioxide was produ

Aliun [14]

Answer:

Percent yield = 50%

Explanation:

Given data:

Mass of CH₄ = 16 g

Mass of O₂ = 32 g

Mass of CO₂ = 11 g

Percent yield of CO₂ = ?

Solution:

Chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/ molar mass

Number of moles = 16 g /16 g/mol

Number of moles = 1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 32 g /32 g/mol

Number of moles = 1 mol

Now we will compare the moles of CO₂ with both reactant.

O₂ : CO₂

2 : 1

1 : 1/2×1= 0.5 mol

CH₄ : CO₂

1 : 1

Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.

Theoretical yield:

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 11 g/ 22 g × 100

Percent yield = 50%

3 0

3 years ago

Carbon dioxide gas is collected at 27.0(degrees)C in an evacuated flask with a measured volume of 30.0L. When all the gas has be

White raven [17]

Answer:

Moles of carbon dioxide gas is 0.584 moles.

Mass of 0.584 moles of carbon dioxide gas is 25.7 g

Explanation:

Using ideal gas equation

PV = nRT

where,

P = Pressure of gas = $0.480 atm$

V = Volume of gas = 30.0 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 27°C = 300.15 K

Putting values in above equation, we get:

$(0.480 atm)\times 30.0 L=n\times (0.0821L.atm/mol.K)\times 300.15K\\\\n=0.5844 mol\approx 0.584$

Moles of carbon dioxide gas = 0.584 moles

Mass of 0.584 moles of carbon dioxide gas = 0.584 mol × 44 g/mol = 25.69 g ≈ 25.7 g

5 0

3 years ago