The following is what type of reaction: A + B → C

What is the purpose of the sojourner rover ????

Feliz [49]

Answer:

Sojourner is the Mars Pathfinder robotic Mars rover that landed on July 4, 1997 in the Ares Vallis region, and explored Mars for around three months. It has front and rear cameras and hardware to conduct several scientific experiments.

Explanation:

8 0

3 years ago

The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?

soldier1979 [14.2K]

Answer: Volume of 1g of pure gold $v=0.05181 \mathrm{cm}^{3}$

Given;

Density of a pure gold=19.3 $g / c m^{3}$

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

$\rho=m / v$

Where $\rho$ =density of pure gold

m=mass of pure gold

v=volume of pure gold

From the above equation volume can be calculated as

$v=m / \rho$

Substitute the values of mass and density value in the above equation

$v=1 / 19.3$

$v=0.05181 \mathrm{cm}^{3}$

Result:

Thus the volume of 1g of pure gold is $v=0.05181 \mathrm{cm}^{3}$

8 0

3 years ago

Calculate the concentration 3.8g of copper sulfate, CuSO4 dissolved in 250cm4 of water

11Alexandr11 [23.1K]

Answer:

Molarity = 0.08 M

Explanation:

Given data:

Mass of copper sulfate = 3.8 g

Volume of water = 250 cm³ (250/1000 = 0.25 L)

Concentration of solution = ?

Solution:

Number of moles of copper sulfate:

Number of moles = mass/molar mass

Number of moles = 3.8 g/ 159.6 g/mol

Number of moles = 0.02 mol

Concentration:

Molarity = Number of moles / volume in L

By putting values,

Molarity = 0.02 mol / 0.25 L

Molarity = 0.08 mol/L

Molarity = 0.08 M

6 0

3 years ago

August kekule described the various ring structures of the carbon compound benzene. What type of chemist would he be considered

Andreyy89

B. He would be considered an Organic Chemist since Organic Chemistry is the study of Carbon and its compounds.

3 0

3 years ago

Read 2 more answers

When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr

poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

$E=-13.6*Z^{2}*(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} ) eV$

For the H transition n=5 to n=2:

$E=-13.6*(\frac{1}{4}-\frac{1}{25} ) eV=-2.856 eV$

Then we solve for nf with Z=2 (Helium)

$n_{f}=\sqrt{\frac{n_{i}^{2}*Z^{2}*13.6 eV }{2.856eV*n_{i}^{2}+13.6eV*Z^{2}} }$

$n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3$

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

4 0

3 years ago