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castortr0y [4]
3 years ago
13

Why does a reaction involving a catalyst finally stop

Chemistry
2 answers:
umka21 [38]3 years ago
8 0

Answer:

Explanation:

Catalysis is a process that accelerates chemical reactions due to molecules called catalysts, which provide ways to reach products that require less energy.

A catalyst intervenes in the reaction mechanism, but is not consumed. This means that the catalyst participates in some stage of the reaction, but then regenerates.

In addition, a catalyst is used in a small amount: a minimum mole percentage, with respect to reagents, is usually required to observe an increase in velocity.

There are three types of catalysis:

  • Homogeneous: the catalyst is present in the same phase as the species that react.
  • Heterogeneous: the catalyst and reagents are in a different phase.
  • Enzyme: occurs only in living beings, and in these cases the catalysts are enzymes.

The absence of a catalyst can make the reaction so slow that it never occurs. Therefore, when the catalyst of a reaction is removed, the reaction may stop.

elena55 [62]3 years ago
7 0
<span>When the catalyst is a reaction is removed by the reaction, this reaction will stop as there won't be any agent causing it anymore. !</span>
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Identify the neutralization reaction.
dusya [7]

The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.

<h3>What is a neutralization reaction?</h3>

It is a reaction involving an acid and a base to produce salt and water.

From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.

Thus, the neutralization reaction is represented by the equation:

2H_3PO_4 + 3Ba(OH)_2 --- > 6H_2O + Ba(PO_4)_2

More on neutralization reactions can be found here: brainly.com/question/20038776

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4 0
2 years ago
Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?
Brrunno [24]

Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.30 atm

P_2 = final pressure of gas = 5.40 atm

V_1 = initial volume of gas = 20.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 308 K

T_2 = final temperature of gas = 416 K

Now put all the given values in the above equation, we get:

\frac{2.30atm\times 20.0L}{308K}=\frac{5.40atm\times V_2}{416K}

V_2=11.5L

Therefore, the final volume of gas is, 11.5 L

7 0
3 years ago
Read 2 more answers
Which great scientist is considered one of the most important scientists in history, developed the theory of gravity and the law
Wewaii [24]

Answer:

Newton

Explanation:

ive answered like 3 of these types of questions today lol

5 0
3 years ago
Read 2 more answers
The first part of a balanced chemical equation for a chemical reaction is shown below:
Bond [772]

Answer:

The answer to your question is 6

Explanation:

Data

              Cu  +  2AgNO₃   ⇒  

To find the answer, count the number of each element in the reactants

Element                Quantity

Copper                        1

Silver                           2

Nitrogen                      1

Oxygen                        6

Then, in the products, there must be 6 oxygens so in the products there must be 6 oxygens so the reaction is balanced.              

8 0
3 years ago
Under certain conditions, the substance calcium carbonate can be broken down to form calcium oxide and carbon dioxide. If 31.7 g
klio [65]

Answer:

13.93\ \text{g}

Explanation:

Molecular weight of CaCO_3 = 100.0869 g/mol

Mass of CaCO_3 = 31.7 g

Moles of CaCO_3 = \dfrac{31.7}{100.0869}=0.3167\ \text{mol}

Moles of both CaO and CO_2 is 0.3167\ \text{mol}

Molecular weight of CO_2 = 44 g/mol

Mass of CO_2 = 44\times 0.3167=13.93\ \text{g}

The mass of carbon dioxide formed simultaneously is 13.93\ \text{g}.

6 0
3 years ago
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