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3 years ago

Why does a reaction involving a catalyst finally stop

Chemistry

2 answers:

umka21 [38]3 years ago

8 0

Answer:

Explanation:

Catalysis is a process that accelerates chemical reactions due to molecules called catalysts, which provide ways to reach products that require less energy.

A catalyst intervenes in the reaction mechanism, but is not consumed. This means that the catalyst participates in some stage of the reaction, but then regenerates.

In addition, a catalyst is used in a small amount: a minimum mole percentage, with respect to reagents, is usually required to observe an increase in velocity.

There are three types of catalysis:

Homogeneous: the catalyst is present in the same phase as the species that react.
Heterogeneous: the catalyst and reagents are in a different phase.
Enzyme: occurs only in living beings, and in these cases the catalysts are enzymes.

The absence of a catalyst can make the reaction so slow that it never occurs. Therefore, when the catalyst of a reaction is removed, the reaction may stop.

elena55 [62]3 years ago

7 0

When the catalyst is a reaction is removed by the reaction, this reaction will stop as there won't be any agent causing it anymore. !

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Alexeev081 [22]

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3 years ago

Which TWO statements describe the ocean floor giving brainliest pls help explain ur answer

Gelneren [198K]

Answer:

Dude im not 100% sure but I think its b and c im sorry if im wrong its just that im not really sure which ones are.

Explanation:

8 0

3 years ago

Calculate the pH of the following simple solutions:

IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

(1) 53.1 mM HCl

Concentration of HCl = $53.1mM=53.1\times 10^{-3}M$

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= $53.1\times 10^{-3}M$

pH : It is defined as the negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH=-\log (53.1\times 10^{-3})$

$pH=1.27$

(2) 0.223 M KOH

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (0.223)$

$pOH=0.65$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35$

(3) 53.1 mM HCl + 0.223 M KOH

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

5 0

3 years ago

Which statements are true of the reaction below? 2na(s) + cl2(g) 2nacl(s) Check all that apply. A - NaCl is a product B - Na(s)

Bumek [7]

Answer:

A - NaCl is a product

D - Cl2 is a gas

Explanation:

Based on the chemical reaction;

2Na(s) + Cl2(g) → 2NaCl2

Sodium metal reacts with chlorine gas to form sodium chloride. Sodium is in solid state, chlorine is in gaseous state and Sodium chloride is in solid state.
In the chemical reaction, sodium and chlorine are reactants while sodium chloride is the product.
Additionally the chemical reaction above is balanced so as to obey the law of conservation of mass.

4 0

4 years ago

How many moles of sodium (Na) are there in a sample of 5.87 x 1024 atoms of sodium?

Leno4ka [110]

9.74x 2351 that's the answer

6 0

3 years ago