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Varvara68 [4.7K]

3 years ago

7

What type(s) of intermolecular forces are expected between nocl molecules?

1 answer:

mina [271]3 years ago

4 0

If you draw or search for the molecular geometry of NOCl, you would know that it has a bent shape. This bent shape is a characteristic of a polar molecule. The dominant intermolecular forces for polar compounds is the <em>dipole-dipole force</em>.

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How many grams of solute are needed to make 2.50 L of a 1.75 M solution of Ba(NO3)2?

Eddi Din [679]

1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles can be calculated by using the following formula:

Molarity = no of moles ÷ volume

no of moles = 1.75 × 2.5

no of moles = 4.38mol

molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 4.38

mass of Ba(NO3)2 = 1143.4grams.

Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.

Learn more about mass at: brainly.com/question/19694949

3 0

2 years ago

A bottle of sulfuric acid has a mass of 18.45 g and a density of 4.37 g/mL. What is the volume?

SpyIntel [72]

B). 4.22 mL
Do 18.45g/ 4.37gmL

7 0

3 years ago

PLEASE HELP ASAP FOR 25 POINTS!! :D

kondaur [170]

the x y axis is tipped so the earth is flat

3 0

3 years ago

You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out

mina [271]

Answer:

The diameter of the oil molecule is $4.4674\times 10^{-8} cm$ .

Explanation:

Mass of the oil drop = $m=9.00\times 10^{-7} kg$

Density of the oil drop = $d=918 kg/m^3$

Volume of the oil drop: v

$d=\frac{m}{v}$

$v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}$

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = $4\pi r^2$

$a=4\times 3.14\times (0.418 m)^2=2.1945 m^2$

Volume of the oil drop = v = Area × thickness

$\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x$

$x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm$

The thickness of the oil drop is $4.4674\times 10^{-8} cm$ and so is the diameter of the molecule.

6 0

3 years ago

Students can use _________ to distinguish pure substances, such as elements and compounds with a constant composition, from othe

ollegr [7]

Density ........on god thats the answer

3 0

3 years ago

Read 2 more answers