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mel-nik [20]
3 years ago
5

Dissolving a solute such as koh in a solvent such as water results in

Chemistry
2 answers:
GalinKa [24]3 years ago
6 0
Answer : Decrease in the vapour pressure of the liquid.

Explanation : 
When a solute is dissolved in a solvent it decreases the vapour pressure of the solvent. Usually the vapour pressure of the solution after mixing the solute is found to be lower than the vapour pressure of the pure solvent.

It is also dependent on the concentration of the solute. 
andreev551 [17]3 years ago
4 0
Answer;
A decrease in the vapor pressure of the liquid. 

Dissolving a solute such as potassium hydroxide in a solvent such as water results in a decrease in the vapor pressure of the liquid. 

Explanation; 
The vapor pressure of a liquid is the equilibrium of a vapor above its liquid.
In other words it is the pressure of the vapor resulting from the evaporation of a liquid above a given sample of the liquid in a closed container.
The vapor pressure of a liquid in a closed container depends on the temperature.
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Match each substance with the correct designation for the equation HSO3- + CH3NH2 <=> SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
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Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

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Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

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3 years ago
When determining the mass of product used or reactant consumed, the number of moles must be determined before comparing two subs
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Answer:

moles react.

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