The sum of two numbers 54. Their difference is 34
1 answer:
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Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
Answer:
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference
The formula for an Arithmetic Sequence is equal to
where
d is the common difference
n is the number of terms
a_1 is the first term of the sequence
In this problem we have
substitute
so
<u><em>Find the first ten terms</em></u>
For n=2 ---->
For n=3 ---->
For n=4 ---->
For n=5 ---->
For n=6 ---->
For n=7 ---->
For n=8 ---->
For n=9 ---->
For n=10 ---->
The sequence is