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Mila [183]
3 years ago
7

1362205.2 in scientific notation

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
8 0
1.3622052x10^6 you move the . 6 places to the left making it a positive 10^6
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Write a short story in about 150 to 200 words based on the image given below​
antoniya [11.8K]
Dude, writing someone else’s story or essay isn’t allowed, so i’ll just give some pointers

so the dude on the throne, a monarch, most likely the king, has a diamond or some other precious object in his hand. meanwhile, there’s a dude sitting on the floor, he looks unhappy, distressed, and maybe a little surprised. so what do you think happened to get to this point? what or who gave the king the diamond? why is the dude on the floor upset? then what’s going to happen? what’s the upset dude gonna
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3 years ago
All the following steps need to be followed when naming alkanes, except
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A.

Begin numbering at the end closest to the first branch, not the farthest.  

6 0
4 years ago
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The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5. calculate the ph of a 1.60 m acetic acid solution.
leonid [27]

<span>To determine the pH of the solution given, we make use of the acid equilibrium constant (Ka) given. It is the ratio of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the CH3COOH acid would be as follows:

</span>CH3COOH = CH3COO- + H+<span>

The acid equilibrum constant would be expressed as follows:

Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5

<span>
To determine the equilibrium concentrations we use the ICE table,
         CH3COOH             H+             </span>CH3COO<span>-
I            1.60                    0                     0
C             -x                    +x                   +x
----------------------------------------------------------------
E         1.60-x                   x                     x 

</span>1.8× 10^–5 =  [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>

Solving for x,

x = 1.69x10^-3 = [H+] = [F-]

pH = -log [H+] = -log [1.69x10^-3] = 2.8

8 0
3 years ago
I NEED HELP!!! I WILL RATE BRAINLIEST!!!!
icang [17]
It is 3 moles. Don't doubt urself
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4 years ago
How many chiral centres are there in warfarin molecule?
kolbaska11 [484]
I'm actually not sure... but maybe this will help!
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