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Serjik [45]
2 years ago
8

Which statement holds true when the molar mass of hydrogen is 2.0 grams and that of helium is 4.0 grams? Hydrogen effuses 1.4 ti

mes faster than helium. Hydrogen effuses 0.71 times faster than helium. Helium effuses 1.4 times faster than hydrogen. Helium effuses 0.71 times faster than hydrogen. The rate of effusion of both gases is the same.
Chemistry
1 answer:
SIZIF [17.4K]2 years ago
3 0
Answer:
             <span>Hydrogen effuses 1.4 times faster than Helium.

Explanation:
                   According to Graham's Law of Effusion, "the rate of effusion of a gas is inversely proportional to the square root of its density or molar mass".

Mathematically,
                                       R</span>ₐ / Rₓ  =  \sqrt{Mx/Ma}    ----- (1)
Where;
            Rₐ  =  Rate of effusion of H₂

            Rₓ  =  Rate of effusion of He

            Mₐ  =  Molar Mass of H₂  =  2 g.mol⁻¹

            Mₓ  =  Molar Mass of He  =  4 g.mol⁻¹

Putting values in equation 1,

                                       Rₐ / Rₓ  =  \sqrt{4/2}

                                       Rₐ / Rₓ  =  \sqrt{2}

                                       Rₐ / Rₓ  =  1.41

Result:
          Hence, H₂ effuses 1.41 times faster than He.
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Answer:

126.8, Iodine

Explanation:

  • mass ×abundance/100
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<em>IODINE</em><em> </em><em>has</em><em> </em><em>an</em><em> </em><em>atomic</em><em> </em><em>mass</em><em> </em><em>of</em><em> </em>126.8 or 126.9

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2 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
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3 years ago
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A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose
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Answer:

2.6%

Explanation:

As, 1 ounce (oz) =  0.0625 pounds (lb)

Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb

Since, 1 oz =  0.0625 lb

⇒ 4 oz = 4×0.0625 = 0.25 lb

Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb

The <u>amount of weight lost</u> is equal to the difference of weight of the baby at birth and discharge.

Therefore, <u>weight lost</u> = 7.25 lb - 7.0625 lb = <u>0.1875 lb</u>

Now, the <u>percentage of weight lost</u> by the baby is given by the amount of weight lost divided by the weight of the baby at birth.

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3 years ago
A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. Wha
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We have that the molecular weight (3sf) of the compound (g/mol)

m=44.15g/mol

From the question we are told

A solution made by mixing 20.0 g of a non-volatile compound with 125 mL of water at 25°C has a vapor pressure of 22.67 torr. What is the molecular weight (3sf) of the compound (g/mol).

Generally the equation for the Rouault's law is mathematically given as

P=P_0 N

22.67=23.8*\frac{\frac{12.5}{18}}{\frac{125}{18}+\frac{15}{m}}\\\\\6.95+\frac{15}{m}=7.29\\\\\frac{15}{m}=7.29-6.95\\\\m=\frac{15}{0.34}\\\\m=44.11g/mol

Therefore

The molecular weight (3sf) of the compound (g/mol)

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