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Serjik [45]
2 years ago
8

Which statement holds true when the molar mass of hydrogen is 2.0 grams and that of helium is 4.0 grams? Hydrogen effuses 1.4 ti

mes faster than helium. Hydrogen effuses 0.71 times faster than helium. Helium effuses 1.4 times faster than hydrogen. Helium effuses 0.71 times faster than hydrogen. The rate of effusion of both gases is the same.
Chemistry
1 answer:
SIZIF [17.4K]2 years ago
3 0
Answer:
             <span>Hydrogen effuses 1.4 times faster than Helium.

Explanation:
                   According to Graham's Law of Effusion, "the rate of effusion of a gas is inversely proportional to the square root of its density or molar mass".

Mathematically,
                                       R</span>ₐ / Rₓ  =  \sqrt{Mx/Ma}    ----- (1)
Where;
            Rₐ  =  Rate of effusion of H₂

            Rₓ  =  Rate of effusion of He

            Mₐ  =  Molar Mass of H₂  =  2 g.mol⁻¹

            Mₓ  =  Molar Mass of He  =  4 g.mol⁻¹

Putting values in equation 1,

                                       Rₐ / Rₓ  =  \sqrt{4/2}

                                       Rₐ / Rₓ  =  \sqrt{2}

                                       Rₐ / Rₓ  =  1.41

Result:
          Hence, H₂ effuses 1.41 times faster than He.
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Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
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The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

ρ=mVm\s=ρ×Vm\s=0.749g/mL×2384.mLm\s=1786.2g

We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

brainly.com/question/13996238

#SPJ4

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