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Anastasy [175]
3 years ago
10

A 0.51 m aqueous solution of an unknown solute has a boiling point elevation of 0.62°c. The boiling point elevation of a 0.51 m

solution of a non-electrolyte solute in water is 0.26°c. How many moles of particles are formed per mole of solute when the unknown solute is dissolved in water?
Chemistry
1 answer:
Nadusha1986 [10]3 years ago
5 0

cccccccccccccccccccccccccccccccccccc

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What mass of Iron (III) acetate will be produced when 1.50 grams of iron reacts in acetic acid?
pantera1 [17]

Answer:

2Fe + 6HC2H3O2 → 2Fe(C2H3O2)3 + 3H2

Explanation:

There you go

4 0
3 years ago
Which aldehyde is an intermediate in the reduction of ethyl benzoate with lithium aluminum hydride?
garri49 [273]

Answer:

tetrahedral aldehyde

Explanation:

  1. The reaction begins with a hydride nucleophile reacting with the ester carbonyl carbon to form the tetrahedral intermediate.
  1. The carbonyl reforms to produce an aldehyde with the loss of the alkoxide ion.
  2. The resulting aldehyde undergoes a subsequent reaction with a hydride nucleophile to form another tetrahedral intermediate. The carbonyl is not able to reform, because there are no stable leaving groups.
  3. Therefore, the tetrahedral intermediate is protonated to produce a primary alcohol.
6 0
3 years ago
2MG+O2 ...........2MGO
Galina-37 [17]
Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

= 20 g of MgO produced
5 0
3 years ago
The reducing agent in the reaction described in Fe + 2HCl → FeCl2 + H2 is A. H2. B. Fe. C. HCl. D. FeCl2.
Fed [463]
The reducing agent is b). Fe
7 0
3 years ago
Read 2 more answers
How many neon atoms are contained in (7.27x10^2) grams of neon?
statuscvo [17]

Answer: 2.19x10^25 atoms

Explanation:

Molar Mass of Neon = 20g/mol

1mole(20g) of Neon contains 6.02x10^23 atoms.

Therefore, 7.27x10^2g of Neon will contain x atoms i.e

X atoms = (7.27x10^2x6.02x10^23)/20 = 2.19x10^25 atoms

4 0
3 years ago
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