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lora16 [44]
3 years ago
11

When an aqueous solution of sodium phosphate (Na3PO4) and an aqueous solution of magnesium sulfate (MgSO4) are mixed, a precipit

ate forms. Write the chemical formula of the precipitate.
Chemistry
1 answer:
Akimi4 [234]3 years ago
8 0

Answer: The chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

Explanation:

An equation which depicts the chemical reaction of substances in the form of chemical formulas is called a chemical equation.

For example, chemical equation for an aqueous solution of sodium phosphate (Na_{3}PO_{4}) and an aqueous solution of magnesium sulfate (MgSO_{4}) are mixed, a precipitate forms is as follows.

3MgSO_{4}(aq) + 2Na_{3}PO_{4}(aq) \rightarrow Mg_{3}(PO_{4})_{2}(s) + 3Na_{2}SO_{4}(aq)

Here, trimagnesium phosphate is the precipitate. The chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

Thus, we can conclude that the chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

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You have 846 ml of 3.95 M HCl. Using a volumetric pipet, you take 268 ml of that solution and dilute it to 803 ml in a volumetri
Anettt [7]

Answer: The concentration of hydrochloric acid in the final solution is 0.72 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 3.95 M

V_1 = volume of stock solution = 268 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 803 ml

3.95\times 268=M_2\times 803

M_2=1.32M

Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.32 M

V_1 = volume of stock solution = 100 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 184 ml

1.32\times 100=M_2\times 184

M_2=0.72M

Thus concentration of hydrochloric acid in the final solution is 0.72 M

7 0
3 years ago
The vapor pressure of pure acetone is 266 torr. When a non-volatile solute is added, the vapor pressure of acetone above the sol
mixas84 [53]

Answer : The mole fraction of the non-volatile solute in the solution is 0.195

Explanation :

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

Formula used :

\frac{\Delta p}{p^o}=X_B

\frac{p^o-p_s}{p^o}=X_B

where,

p^o = vapor pressure of the pure solvent (acetone)  = 266 torr

p_s = vapor pressure of the solution = 214 torr

X_B = mole fraction of solute  = ?

Now put all the given values in the above formula, we get:

\frac{p^o-p_s}{p^o}=X_B

\frac{266-214}{266}=X_B

X_B=0.195

Therefore, the mole fraction of the non-volatile solute in the solution is 0.195

4 0
3 years ago
What is the mass of an object with a volume of 120mL and density of 0.75g/mL?
mafiozo [28]
Mass = density * volume

mass = .75g/mL * 120mL

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