Answer: 1+
Justification:
The ionization energies tell the amount of energy needed to release an electron and form a ion. The first ionization energy if to loose one electron and form the ion with oxidation state 1+, the second ionization energy is the energy to loose a second electron and form the ion with oxidation state 2+, the third ionization energy is the energy to loose a third electron and form the ion with oxidation state 3+.
The low first ionization energy of element 2 shows it will lose an electron relatively easily to form the ion with oxidations state 1+.
The relatively high second ionization energy (and third too) shows that it is very difficult for this atom to loose a second electron, so it will not form an ions with oxidation state 2+. Furthermore, given the relatively high second and third ionization energies, you should think that the oxidation states 2+ and 3+ for element 2 never occurs.
Therefore, the expected oxidation state for the most common ion of element 2 is 1+.
Answer:
Explanation:
Step 1
The question is based on the concept of PH and pOH calculations.
pH is defined as negative logarithmic of hydronium Ion concentration.
while pOH is defined as negative logarithmic of hydroxide ion concentration of the solution.
Step 2
[H+] = 7.7*10-7 M
pH = -log[H+]
= -log ( 7.7*10-7 )
= 6.12
Step 3
pOH = 14 - pH
= 14 - 6.11
= 7.89
Explanation:
The given data is as follows.
, 
Area of the flat plate is 2 × 4 = 8
.
Average convection heat transfer coefficient
=
=
.
Hence, formula to calculate heat transfer through convection from air to the water is given as follows.
q = 
=
= 24000 W
or, = 24 kW
Hence, the direction of heat flow is from air to the surface.
Thus, we can conclude that transfer of heat is 24 kW.
Answer : Option A)
45.5%
Explanation : We use the formula of calculating energy efficiency which is as,
η (in %)= [

] X 100
where η is energy efficiency,
and P values are for energy out and in.
So plugging the given values, we get,
η (in %) = (11825.5 / 25978.8) X 100 =
45.5 %