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3 years ago

What is the solution set to the inequality 5(x - 2)(x + 4) > 0?

Mathematics

1 answer:

Butoxors [25]3 years ago

8 0

Answer:

You selected the correct answer: {x | x < -4 or x > 2}

Step-by-step explanation:

5(x - 2)(x + 4) > 0

Use FOIL method to expand (x - 2)(x + 4):

$5(x^{2} + 2x - 8)$ > 0

Distribute 5 into $(x^{2} + 2x - 8)$

$5x^{2} + 10x - 40$ > 0

Divide all terms by 5 from both sides of the inequality:

$\frac{5x^{2}}{5} + \frac{10x}{5} - \frac{40}{5} > \frac{0}{5}$

$x^{2} + 2x - 8 > 0$

Factor the trinomial:

(x + 4) ( x - 2) > 0

x < -4 or x > -2

Therefore, the solution set to the inequality is {x | x < -4 or x > 2}

Interval notation: (-∞, -4) ∪ (2, ∞)

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The sum of the areas of two circles is 8pie square meters. Find the length of a radius of each circle ifone of them is twice as

NeX [460]

Nice

area=pir^2
the areas are
pir^2+pi(2r)^2
they add to 8pi

8pi=pir^2+pi(2r)^2
undistribute pi
8pi=pi(r^2+(2r)^2)
divide both sides by pi
8=r^2+(2r)^2
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Step-by-step explanation:

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Answer:

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Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

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3 years ago

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