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2 years ago

Solve for the value of d.

Mathematics

2 answers:

Anettt [7]2 years ago

7 0

9°

Step-by-step explanation:

In the given diagram we see that both the angles are complementary i.e. they form an angle of 90°

So therefore,

According to the question

$(6d + 8) + (3d + 1) = 90$

$= > 9d = 90 - 8 - 1$

$= > 9d = 81$

$= > d = \frac{81}{9}$

$= > d = 9$

Answer - d = 9°

Hope it helps you!!

#IndianMurgaツ

serg [7]2 years ago

5 0

Answer:

d is 9

Step-by-step explanation:

(6d+8) + (3d+1)=90

9d +9=90

9d=90-9

9d =81

d=81/9

d is 9

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Tell whether the lines through the given points are parallel, perpendicular, or neither.

antoniya [11.8K]

Answer:

The Slope of Line 1 is -> $-\frac{2}{9}$

The Slope of Line 2 is -> $-\frac{9}{2}$

These two lines are - > Perpendicular

Step-by-step explanation:

To find the slope of line one, you follow these steps:

First Coordinate 10 -> x1, 5 -> y1

Second Coordinate -8 -> x2, 9 -> y2

Then insert the assigned values into this equation: $\frac{y2-y1}{x2-x1}$ -> $\frac{9-5}{-8-10}$ which equals $\frac{4}{-18}$ which simplifies to $-\frac{2}{9}$

Then do the same process to find the slop of line 2:

First Coord: 2 -> x1, -4 -> y1

Second Coord: 11 -> x2, -6 -> y2

Then insert the values into this equation: $\frac{y2-y1}{x2-x1}$ -> $\frac{11-2}{-6-(-4)}$ which equals $\frac{9}{-2}$ .

We know the lines are perpendicular by:

a. Typing the equations of the lines into a graphing calculator and observing the graph

b. Looking at the slopes. By looking at the slopes, we see that the slope of line 1 is the reciprocal of line 2, and vice versa. Since reciprocal slopes indicate perpendicular lines, the lines 1 and 2 are perpendicular to each other.

Hope this helps!

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3 years ago

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jonny [76]

Answer:

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Answer:

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Step-by-step explanation:

time spent on the thread mill as a function of d(day) = t(d)

= 30 +2(d-1) minutes

[where d represents day number]

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so substitute d=1 and check it will be 30 only.

on first day he will spend 30 minutes so, I added 30 .

and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)

so, T(6), the minutes he will spend on the treadmill on day 6=

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