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2 years ago

Solve for the value of d.

Mathematics

2 answers:

Anettt [7]2 years ago

7 0

9°

Step-by-step explanation:

In the given diagram we see that both the angles are complementary i.e. they form an angle of 90°

So therefore,

According to the question

$(6d + 8) + (3d + 1) = 90$

$= > 9d = 90 - 8 - 1$

$= > 9d = 81$

$= > d = \frac{81}{9}$

$= > d = 9$

Answer - d = 9°

Hope it helps you!!

#IndianMurgaツ

serg [7]2 years ago

5 0

Answer:

d is 9

Step-by-step explanation:

(6d+8) + (3d+1)=90

9d +9=90

9d=90-9

9d =81

d=81/9

d is 9

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You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

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Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$