<span>Find the inverse of the given function.
f(x) = -1/2√x + 3, x ≥ -3
I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3. If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.
1. Replace "f(x)" by "y:" y </span>= -(1/2)sqrt(x) + 3
2. Interchange x and y: x = -(1/2)sqrt(y) + 3
3. Solve for y: x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4. Replace "y" with
-1
f (x) = sqrt(2[3-x])
Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers. The domain here is (-infinity,3]
Answer:
Step-by-step explanation:
PEMDAS (order of operations)
2 times 8=16
18/3= 6
16+5-6=15
Answer:
C. c = 64 + 2w
Step-by-step explanation:
You're starting with 64 customers and you're gaining 2 for each week.
<em>good luck, i hope this helps :)</em>
Hi there! The answer is A.
Graph A. is not linear because it contains x^2 and therefore is a quadratic function.
Answer:
the third one
Step-by-step explanation:
