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Law Incorporation [45]
3 years ago
15

3/4 = j−12. Algebra

Mathematics
2 answers:
romanna [79]3 years ago
7 0
3/4 = .75

Next you do this; .75 + 12
.
75 + 12 = 12.75

12.75 will be your answer
Studentka2010 [4]3 years ago
6 0
First, we simplify this to 3/4-j/12=0. 4/4=1 so we do, -j=-51/4*-1. Therefore, the answer is j=51/4. Hoped I helped. :)
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Identify the TRUE statement relating to a property of the function y = sin x
svlad2 [7]

The true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

<h3>Properties of the function</h3>

The following are the properties of the sin trigonometric ratio of the function;

  • The sine graph rises till +1 and then falls back till -1 from where it rises again.
  • The function y = sin x is an odd function
  • The domain of y = sin x is the set of all real numbers
  • The range of sine function is the closed interval [-1, 1]
  • The amplitude of the function is half its range value
  • One cycle of the function is 6. 28

From the above listed deductions, we can see that the true statement about the function y = sin x is that the range which is always known as the maximum and minimum values of the function are 1 and - 1 respectively.

Thus, the true statement relating to a property of the function y =sin x is that the maximum and minimum values of the function are 1 and -1 respectively. Option B

Learn more about the sine function here:

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6 0
2 years ago
18 is what percentage of 25
pentagon [3]

Answer:

Step-by-step explanation:

72%

3 0
3 years ago
Read 2 more answers
3(x+5)= 30 divided by 5
harina [27]

Answer:

x=-3

Step-by-step explanation:

I have a formula

3 0
2 years ago
Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
I need help with my algebra fraction assignments. I need help with page 2, 3,4,5 and 7. I also have additional albebra fraction
PolarNik [594]

Answer:

Step-by-step explanation:

#2 the answer is B, -16/9

do 1/4-5/2

to do this, find the least common denominator. it's 4

1/4-10/4=-9/4

then divide 4 by -9/4. This is the same as 4*-4/9. That is -16/9

#3 the answer is A 9x/x-8

first factor the denominator of the first fraction using special products

x^2-6x-16=(x-8)(x+2)

if you look at the first fraction, you can simplify x+2 leaving you with the fraction 1/x+8

multiply that by 9x, and you get 9x/x-8

#4 the answer is C (2x+1)/2x^2

first add x/4 and 1/8

find the least common denominator. its 8

2x/8 + 1/8 is equal to (2x+1)/8

then multiply that by x^2/4 because dividing a fraction is the same as multiplying its reciprocal

you get (2x+1)/2x^2

#5 the answer is C (x-8)/(x+3)

using special products you can factor the numerator

x^2-4x-32 is the same as (x-8)(x+4)

then, using special products you can also factor the denominator

x^2+7x+12 is the same as (x+4)(x+3)

you can see that both the numerator and the denominator is multiplied by (x+4) you can simplify that. That leaves you with (x-8)/(x+3)

#7 the answer is D 3m

in the numerator in the second fraction, you can factor out 5m^2

leaving you with 5m^2(m-6)/5m^2. simplify the 5m^2 and the m-6

after you simplify both of those, you will get 3m

7 0
3 years ago
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