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gogolik [260]
3 years ago
15

PLEASE HELP! Compare and contrast between reflection and refraction. Be sure to be specific in your explanation and state in you

r own words.
Physics
1 answer:
horsena [70]3 years ago
7 0

Most ultrasound technicians train in an associates degree, but can also get a bachelors degree in the field. There is also certification programs you can go through. Hope this helped!!! :)

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A physics student spends part of her day walking between classes or for recreation, during which time she expends energy at an a
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RESULT: Twalk= 3.64 hr

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2 years ago
A 15 kg box is sliding down an incline of 35 degrees. The incline has a coefficient of friction of 0.25. If the box starts at re
valina [46]

The box has 3 forces acting on it:

• its own weight (magnitude <em>w</em>, pointing downward)

• the normal force of the incline on the box (mag. <em>n</em>, pointing upward perpendicular to the incline)

• friction (mag. <em>f</em>, opposing the box's slide down the incline and parallel to the incline)

Decompose each force into components acting parallel or perpendicular to the incline. (Consult the attached free body diagram.) The normal and friction forces are ready to be used, so that just leaves the weight. If we take the direction in which the box is sliding to be the positive parallel direction, then by Newton's second law, we have

• net parallel force:

∑ <em>F</em> = -<em>f</em> + <em>w</em> sin(35°) = <em>m a</em>

• net perpendicular force:

∑<em> F</em> = <em>n</em> - <em>w</em> cos(35°) = 0

Solve the net perpendicular force equation for the normal force:

<em>n</em> = <em>w</em> cos(35°)

<em>n</em> = (15 kg) (9.8 m/s²) cos(35°)

<em>n</em> ≈ 120 N

Solve for the mag. of friction:

<em>f</em> = <em>µ</em> <em>n</em>

<em>f</em> = 0.25 (120 N)

<em>f</em> ≈ 30 N

Solve the net parallel force equation for the acceleration:

-30 N + (15 kg) (9.8 m/s²) sin(35°) = (15 kg) <em>a</em>

<em>a</em> ≈ (54.3157 N) / (15 kg)

<em>a</em> ≈ 3.6 m/s²

Now solve for the block's speed <em>v</em> given that it starts at rest, with <em>v</em>₀ = 0, and slides down the incline a distance of ∆<em>x</em> = 3 m:

<em>v</em>² - <em>v</em>₀² = 2 <em>a</em> ∆<em>x</em>

<em>v</em>² = 2 (3.6 m/s²) (3 m)

<em>v</em> = √(21.7263 m²/s²)

<em>v</em> ≈ 4.7 m/s

4 0
2 years ago
If a photon of Light leaves the sun than reachers the earth 494 second later. What is the distance from the earth to sun
denis-greek [22]

The distance from the Earth to the Sun is 92.96 million mi.

4 0
3 years ago
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A skateboarder who travels 60 meters in 30 seconds has a speed of
natulia [17]

2m/s

Explanation:

Given parameters:

Distance traveled = 60m

time taken = 30seconds

Unknown:

Speed of skateboarder = ?

Solution:

Speed is the rate of change of distance with time taken. It is a scalar quantity that only revers magnitude;

    Speed = \frac{distance}{time}

    Speed = \frac{60}{30} = 2m/s

learn more:

Speed brainly.com/question/1548911

#learnwithBrainly

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3 years ago
you just saw a magazine ad that shows several people having fun at a football game. They are all wearing a specific shoe brand.
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The answer for the question is bandwagon. Hope it helped :)

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3 years ago
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