Answer: a circluar motion.
Explanation:
Answer: T= 715 N
Explanation:
The only external force (neglecting gravity) acting on the swinging mass, is the centripetal force, which. in this case, is represented by the tension in the string, so we can say:
T = mv² / r
At the moment that the mass be released, it wil continue moving in a straight line at the same tangential speed that it had just an instant before, which is the same speed included in the centripetal force expression.
So the kinetic energy will be the following:
K = 1/2 m v² = 15. 0 J
Solving for v², and replacing in the expression for T:
T = 1.9 Kg (3.97)² m²/s² / 0.042 m = 715 N
Answer:
i think it's 50 N
i might be wrong though not sure
This question involves the concepts of orbital velocity and orbital radius.
The orbital velocity of ISS must be "7660.25 m/s".
The orbital velocity of the ISS can be given by the following formula:
where,
v = orbital velocity = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
M = Mass of Earth = 5.97 x 10²⁴ kg
R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m
R = 67.86 x 10⁵ m
Therefore,
<u>v = 7660.25 m/s</u>
Learn more about orbital velocity here:
brainly.com/question/541239
Answer:
(a) I = 0.6 A
(b) 22.5 * 10^19 electrons
Explanation:
Parameters given:
(a) Current is given as the time Tate of charge flow. Mathematically,
I = Q/t
Charge, Q = 3 C
Time, t = 5 secs
I = 3/5 = 0.6A
(b) The current flowing through the filament is 0.6A. In 1 min (60 secs), the charge will be:
Q = I*t
Q = 0.6 * 60 = 36 C
An electron has a charge, Qe, of 1.6022 * 10^(-19) C. Hence, the number of electrons will be:
N = Q/Qe
N = 36/(1.6022 * 10^(-19))
N = 22.5 * 10^19 electrons