Question

A constant force of 120 N pushes a 55 kg wagon across an 8 m level surface. If the wagon was initially at rest, what is the final kinetic energy of the wagon?

Answer 1

Answer:

The kinetic energy of the wagon is 967.0 J

Explanation:

Given that,

Force = 120 N

Mass = 55 kg

Height = 8 m

We need to calculate the kinetic energy of the wagon

Using newtons law

$F = ma$

$\dfrac{120}{55}=a$

$a =2.2\ m/s^2$

Using equation of motion

$v^2 =u^2+2as$

Where,

v = final velocity

u = initial velocity

s = height

Put the value in the equation

$v^2=0+2\times2.2\times8$

$v=5.93\ m/s$

Now, The kinetic energy is

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times55\times(5.93)^2$

$K.E=967.0\ J$

Hence, The kinetic energy of the wagon is 967.0 J