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3 years ago

GIVING BRAINLIEST PLEASE HELP!!

Physics

1 answer:

AlekseyPX3 years ago

3 0

Answers B and C as energy is stored to use in the following events described

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A 1 500-kg car rounds an unbanked curve with a radius of 52 m at a speed of 12.0 m/s. What minimum coefficient of friction must

Sergio039 [100]

Explanation:

The centripetal force $F_c$ on the car must equal the frictional force f in order to avoid slipping off the road. Let's apply Newton's 2nd law to the y- and x-axes.

$y:\:\:\:\:N - mg = 0$

$x:\:\:F_c = f \Rightarrow \:\:\:m \dfrac{v^2}{r} = \mu N$

$m \dfrac{v^2}{r} = \mu mg$

Solving for $\mu$ ,

$\mu = \dfrac{v^2}{gr} = \dfrac{(12.0\:\frac{m}{s})^2}{(9.8\:\frac{m}{s^2})(52\:m)} = 0.28$

3 0

3 years ago

A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c

sergiy2304 [10]

Answer:

Part a)

$a_{hanger} = g - \frac{T}{m}$

Part b)

$a_{cart} = \frac{T}{M}$

Part c)

$a = \frac{mg}{M + m}$

Part d)

$a = 1.35 m/s^2$

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

$mg - T = ma$

so we have

$a_{hanger} = g - \frac{T}{m}$

Part b)

now for car that is rolling on the floor the net force is given as

$F = Ma$

$T = Ma$

$a_{cart} = \frac{T}{M}$

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

$T = Ma$

$mg - Ma = ma$

$a = \frac{mg}{M + m}$

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

$a = \frac{0.50(9.81)}{2.40 + 0.50}$

$a = 1.35 m/s^2$

6 0

3 years ago

A 200 g mass, attached to a 30 cm long string, travels at a speed of 1.3 ms-1 along horizontal circular path. Relative to the ce

Hunter-Best [27]

T = 2,548

What is tension?

Tension occurs due to the direction of pull on the object and along the length of the given rope.

It's S.I. unit is Newton

Tension formula can be represented as

T = mg + ma

T = 200 (9.8 + 1.3 m/s²)

T = 200 (12.74)

T = 2,548

Learn more about tension : brainly.com/question/15880959

#SPJ1

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2 years ago

The minimum cooking temperature for eggs that will be served immediately is

solong [7]

Cooking and Serving. Cook raw shell eggs that are broken for immediate preparation and service to heat all parts of the food to a temperature of 63°C<span> (</span>145°F<span>) for 15 seconds</span>

5 0

3 years ago

Read 2 more answers

A 0.6 kg ball moving to the right at 12 m/s makes a head on elastic collision with a 0.3 kg ball traveling to the left at 3 m/s.

Anuta_ua [19.1K]

The answer is 0.6 because yea

5 0

2 years ago