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2 years ago

Is calculating the change of velocity the same as calculating acceleration?

Physics

1 answer:

koban [17]2 years ago

4 0

Answer:

Yes! Thinking about it graphically a position vs time graph models meters per second in most cases, making every point on the line have the units m/s. If we want the find the slope we are finding the change between each point and those units would change to m/s/s or m/s^2 giving us the same units for acceleration. Simply put, slope of a velocity graph gives us acceleration.

Explanation:

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g) If two cars A and B are moving with velocity 60 km/hr and 80 km/hr respectively in the same direction. What will be the relat

tester [92]

Explanation:

Here,

Velocity of A=60km/hr

Velocity of B=80km/hr

Now,

Relative velocity of B with respect to A in the same direction=Velocity of B - Velocity of A

=80km/hr-60km/hr

=20km/hr

4 0

1 year ago

I NEED HELP :) ty.............

Black_prince [1.1K]

Answer:

The answer to your question is given below

Explanation:

From the question given above, we can see that the wave with a higher frequency has a shorter wavelength while that with a lower frequency has a longer wavelength. This is so because the frequency and wavelength of a wave has inverse relationship. This can further be explained by using the following formula:

Velocity = wavelength x frequency

Divide both side by wavelength

Frequency = Velocity /wavelength

Keeping the velocity constant, we have:

Frequency ∝ 1 / wavelength

From the above illustration, we can see clearly that the frequency and wavelength are in inverse relationship. This implies that the higher the frequency, the shorter the wavelength and the shorter the frequency, the higher the wavelength.

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2 years ago

A circuit has a voltage drop of 24.0 V across a 30.0 resistor that carries a

beks73 [17]

(A) 19.2 W

Explanation:

Given-

Voltage drop, V = 24 V

Resistor = 30Ω

Current, I = 0.8 A

Power, P = ?

We know,

P = VI

P = 24 (0.8)

P = 19.2 W

Therefore, the power conducted by the resistor is 19.2 W

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2 years ago

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A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.

iris [78.8K]

Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2$

Converting to m/s²

$a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2$

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

$\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g$

Hence, acceleration of the car is -0.64525g

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3 years ago

HELP ME ASAP!!!!100 points!!!!! How do you get your fingers in the Labia?

Nina [5.8K]

You literally just put your fingers in your genitals? is this for a sex ed course...?

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2 years ago

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Is calculating the change of velocity the same as calculating acceleration? ​

Is calculating the change of velocity the same as calculating acceleration?